给定一个十进制整数(例如 65)，如何反转 Python 中的底层位?即以下操作:
Given a decimal integer (eg. 65), how does one reverse the underlying bits in Python? i.e.. the following operation:
65 → 01000001 → 10000010 → 130
看来这个任务可以分解为三个步骤:
It seems that this task can be broken down into three steps:
第 2 步和第 3 步看起来非常简单(请参阅 this 和 this SO 问题与步骤#2) 相关，但我被困在步骤#1.第 1 步的问题是检索完整的十进制表示并填充零(即 65 = 01000001，而不是 1000001).
Steps #2 and 3 seem pretty straightforward (see this and this SO question related to step #2), but I'm stuck on step #1. The issue with step #1 is retrieving the full decimal representation with filling zeros (ie. 65 = 01000001, not 1000001).
我四处寻找，但似乎找不到任何东西.
I've searched around, but I can't seem to find anything.
int('{:08b}'.format(n)[::-1], 2)
您可以指定任何填充长度来代替 8.如果您想要真正花哨，
You can specify any filling length in place of the 8. If you want to get really fancy,
b = '{:0{width}b}'.format(n, width=width)
int(b[::-1], 2)
让您以编程方式指定宽度.
lets you specify the width programmatically.
这篇关于反转 Python 整数的位的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持跟版网！