多处理:在某些情况下,在赋值之前引用变量,但在其他情况下不引用

时间:2023-03-13
本文介绍了多处理:在某些情况下,在赋值之前引用变量,但在其他情况下不引用的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!

问题描述

我在这个网站的某个地方找到了以下示例:

I found the following example on this website somewhere:

import multiprocessing
import ctypes
import numpy as np

shared_array_base = multiprocessing.Array(ctypes.c_double, 10*10)
shared_array = np.ctypeslib.as_array(shared_array_base.get_obj())
shared_array = shared_array.reshape(10, 10)

# No copy was made
assert shared_array.base.base is shared_array_base.get_obj()

# Parallel processing
def my_func(i, def_param=shared_array):
    shared_array[i,:] = i

if __name__ == '__main__':
    pool = multiprocessing.Pool(processes=4)
    pool.map(my_func, range(10))

    print shared_array

上面的代码工作正常,但是如果我想向共享数组添加一个数组,比如 shared_array += some_other_array (而不是上面的 shared_array[i,;] = i)我得到了

The above code works fine, but if I want to add an array to the shared array, something like shared_array += some_other_array (instead of the above shared_array[i,;] = i) I get

赋值前引用的局部变量shared_array"

local variable 'shared_array' referenced before assignment

任何想法为什么我不能这样做?

Any ideas why I cannot do that?

推荐答案

如果一个变量被赋值给函数中的任何地方,它就会被视为一个局部变量.shared_array += some_other_array 等价于 shared_array = shared_array + some_other_array.因此 shared_array 被视为局部变量,当您尝试在赋值右侧使用它时,该变量并不存在.

If a variable is assigned to anywhere in a function, it is treated as a local variable. shared_array += some_other_array is equivalent to shared_array = shared_array + some_other_array. Thus shared_array is treated as a local variable, which does not exist at the time you try to use it on the right-hand side of the assignment.

如果你想使用全局 shared_array 变量,你需要通过在你的函数中放置一个 global shared_array 来显式地将它标记为全局变量.

If you want to use the global shared_array variable, you need to explicitly mark it as global by putting a global shared_array in your function.

您没有看到 shared_array[i,:] = i 错误的原因是它没有分配给变量 shared_array.相反,它改变了该对象,分配给它的一部分.在 Python 中,分配给一个裸名(例如,shared_array = ...)与任何其他类型的分配(例如,shared_array[...] = ...),尽管它们看起来很相似.

The reason you don't see the error with shared_array[i,:] = i is that this does not assign to the variable shared_array. Rather, it mutates that object, assigning to a slice of it. In Python, assigning to a bare name (e.g., shared_array = ...) is very different from any other kind of assignment (e.g., shared_array[...] = ...), even though they look similar.

请注意,顺便说一下,该错误与多处理无关.

Note, incidentally, that the error has nothing to do with multiprocessing.

这篇关于多处理:在某些情况下,在赋值之前引用变量,但在其他情况下不引用的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!

上一篇:具有单个函数的 Python 多处理 下一篇:共享数组在 python 多处理中未正确共享

相关文章