'numpy.float64' 对象不可迭代

时间:2023-01-07
本文介绍了'numpy.float64' 对象不可迭代的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!

问题描述

我正在尝试迭代使用 numpy.linspace 生成的值数组:

I'm trying to iterate an array of values generated with numpy.linspace:

slX = numpy.linspace(obsvX, flightX, numSPts)
slY = np.linspace(obsvY, flightY, numSPts)

for index,point in slX:
    yPoint = slY[index]
    arcpy.AddMessage(yPoint)

这段代码在我的办公室电脑上运行良好,但我今天早上坐在家里的另一台机器上工作,出现了这个错误:

This code worked fine on my office computer, but I sat down this morning to work from home on a different machine and this error came up:

File "C:	empgssm_arcpy.1.0.3.py", line 147, in AnalyzeSightLine
  for index,point in slX:
TypeError: 'numpy.float64' object is not iterable

slX 只是一个浮点数组,脚本打印内容没有问题——只是,显然是迭代它们.关于导致它崩溃的任何建议以及可能的修复方法?

slX is just an array of floats, and the script has no problem printing the contents -- just, apparently iterating through them. Any suggestions for what is causing it to break, and possible fixes?

推荐答案

numpy.linspace() 为您提供一维 NumPy 数组.例如:

numpy.linspace() gives you a one-dimensional NumPy array. For example:

>>> my_array = numpy.linspace(1, 10, 10)
>>> my_array
array([  1.,   2.,   3.,   4.,   5.,   6.,   7.,   8.,   9.,  10.])

因此:

for index,point in my_array

无法工作.您将需要某种二维数组,其中包含两个二维元素:

cannot work. You would need some kind of two-dimensional array with two elements in the second dimension:

>>> two_d = numpy.array([[1, 2], [4, 5]])
>>> two_d
array([[1, 2], [4, 5]])

现在你可以这样做了:

>>> for x, y in two_d:
    print(x, y)

1 2
4 5

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