对于'12233322155552'
这样的字符串,通过去除重复,我可以得到'1235'
.
For a string such as '12233322155552'
, by removing the duplicates, I can get '1235'
.
但我要保留的是'1232152'
,只删除连续的重复项.
import re
# Only repeated numbers
answer = re.sub(r'(d)1+', r'1', '12233322155552')
# Any repeated character
answer = re.sub(r'(.)1+', r'1', '12233322155552')
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