如何使用 Python 通过 Selenium 检索标题属性?

问题描述

这是我的代码:print(browser.find_element_by_partial_link_text(followers").get_attributes(title")).我正在使用 find_element_by_partial_link_text 因为每个用户的 xpath 可能是唯一的.但是我的代码什么也没返回.这是元素的地址:

This is my code : print(browser.find_element_by_partial_link_text("followers").get_attributes("title")). I am using find_element_by_partial_link_text because maybe the xpath could be unique for each user. But my code returns nothing. This is the element's adress:

<li class=" LH36I">
  <a class=" _81NM2" href="/username/followers/">
    <span class="g47SY lOXF2" title="3,862,378">3.8m</span> 
      " followers"
  </a>
</li>

所以我的问题是如何使用 find_element_by_partial_link_text 获取标题中的值?提前致谢.

So my question is how can i get the value in the title using find_element_by_partial_link_text ? Thanks in advance.

已解决:您可以查看 DebanjanB 的答案.

SOLVED : You can look at DebanjanB 's answer.

推荐答案

title 即 3,862,378 的文本不在任何 <a> 标签.因此你不能使用 find_element_by_partial_link_text().此外，该元素是一个动态元素，因此您必须为所需的 visibility_of_element_located() 诱导 WebDriverWait，您可以使用以下解决方案:

The text of the title i.e. 3,862,378 isn't within any <a> tag. Hence you can't use find_element_by_partial_link_text(). Moreover the element is a dynamic element so so you have to induce WebDriverWait for the desired visibility_of_element_located() and you can use the following solution:

• 使用 XPATH:

print(WebDriverWait(browser, 20).until(EC.visibility_of_element_located((By.XPATH, "//a[@href='/username/followers/' and contains(., 'followers')]/span"))).get_attribute("title"))

print(WebDriverWait(browser, 20).until(EC.visibility_of_element_located((By.CSS_SELECTOR, "a[href='/username/followers/']>span"))).get_attribute("title"))

注意:根据文档，实际方法是 get_attribute(name) 但不是 get_attributes()

Note: As per the documentation the actual method is get_attribute(name) but not get_attributes()

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