对列表中的元素求和

问题描述

这是我的代码，我需要对列表中未定义数量的元素求和.如何做到这一点?

l = raw_input()l = l.split(' ')l.pop(0)

我的输入:3 5 4 9输入后，我通过 l.pop(0) 删除第一个元素.在 .split(' ') 我的列表是 ['5', '4', '9'] 之后，我需要对这个列表中的所有元素求和.p>

在这种情况下，总和为 18.请注意，未定义元素的数量.

您可以简单地使用 sum() 内置:

sum(your_list)

它将汇总您拥有的尽可能多的数字项.示例:

my_list = range(10, 17)我的清单[10、11、12、13、14、15、16]总和(我的列表)91

针对您的具体情况:

对于您的数据，首先将数字转换为 int，然后将数字相加:

数据 = ['5', '4', '9']sum(int(i) for i in data)18

这适用于列表中未定义数量的元素(只要它们是数字")

感谢@senderle 的注释重新转换，以防数据为字符串格式.

Here is my code, I need to sum an undefined number of elements in the list. How to do this?

l = raw_input()
l = l.split(' ')
l.pop(0)

My input: 3 5 4 9 After input I delete first element via l.pop(0). After .split(' ') my list is ['5', '4', '9'] and I need to sum all elements in this list.

In this case the sum is 18. Please notice that number of elements is not defined.

You can sum numbers in a list simply with the sum() built-in:

sum(your_list)

It will sum as many number items as you have. Example:

my_list = range(10, 17)
my_list
[10, 11, 12, 13, 14, 15, 16]

sum(my_list)
91

For your specific case:

For your data convert the numbers into int first and then sum the numbers:

data = ['5', '4', '9']

sum(int(i) for i in data)
18

This will work for undefined number of elements in your list (as long as they are "numbers")

Thanks for @senderle's comment re conversion in case the data is in string format.

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