我想在 PHP 中以 Paul Eggert 格式(America/New_York
)的时区获取今天的日期?
I want to get todays date given a time zone in Paul Eggert format(America/New_York
) in PHP?
其他答案设置系统中所有日期的时区.如果您想为用户支持多个时区,这并不总是有效.
The other answers set the timezone for all dates in your system. This doesn't always work well if you want to support multiple timezones for your users.
这是简短的版本:
<?php
$date = new DateTime("now", new DateTimeZone('America/New_York') );
echo $date->format('Y-m-d H:i:s');
适用于 PHP >= 5.2.0
Works in PHP >= 5.2.0
支持的时区列表:php.net/manual/en/timezones.php
这是一个有现有时间并通过用户设置设置时区的版本
Here's a version with an existing time and setting timezone by a user setting
<?php
$usersTimezone = 'America/New_York';
$date = new DateTime( 'Thu, 31 Mar 2011 02:05:59 GMT', new DateTimeZone($usersTimezone) );
echo $date->format('Y-m-d H:i:s');
<小时>
这里有一个更详细的版本,可以更清楚地展示这个过程
Here is a more verbose version to show the process a little more clearly
<?php
// Date for a specific date/time:
$date = new DateTime('Thu, 31 Mar 2011 02:05:59 GMT');
// Output date (as-is)
echo $date->format('l, F j Y g:i:s A');
// Output line break (for testing)
echo "
<br />
";
// Example user timezone (to show it can be used dynamically)
$usersTimezone = 'America/New_York';
// Convert timezone
$tz = new DateTimeZone($usersTimezone);
$date->setTimeZone($tz);
// Output date after
echo $date->format('l, F j Y g:i:s A');
<小时>
我确信还有许多其他可用的库,但这些是我熟悉的一些.
当你在这里的时候,让我为你省去一些未来的头痛.假设您要计算从今天开始的 1 周和从今天开始的 2 周.你可能会写一些类似的代码:
While you're here, let me save you some future headache. Let's say you want to calculate 1 week from today and 2 weeks from today. You might write some code like:
<?php
// Create a datetime (now, in this case 2017-Feb-11)
$today = new DateTime();
echo $today->format('Y-m-d') . "
<br>";
echo "---
<br>";
$oneWeekFromToday = $today->add(DateInterval::createFromDateString('7 days'));
$twoWeeksFromToday = $today->add(DateInterval::createFromDateString('14 days'));
echo $today->format('Y-m-d') . "
<br>";
echo $oneWeekFromToday->format('Y-m-d') . "
<br>";
echo $twoWeeksFromToday->format('Y-m-d') . "
<br>";
echo "
<br>";
输出:
2017-02-11
---
2017-03-04
2017-03-04
2017-03-04
嗯...这不是我们想要的.在 PHP 中修改传统的 DateTime
对象不仅会返回更新的日期,还会修改原始对象.
Hmmmm... That's not quite what we wanted. Modifying a traditional DateTime
object in PHP not only returns the updated date but modifies the original object as well.
这就是 DateTimeImmutable
的用武之地.
This is where DateTimeImmutable
comes in.
$today = new DateTimeImmutable();
echo $today->format('Y-m-d') . "
<br>";
echo "---
<br>";
$oneWeekFromToday = $today->add(DateInterval::createFromDateString('7 days'));
$twoWeeksFromToday = $today->add(DateInterval::createFromDateString('14 days'));
echo $today->format('Y-m-d') . "
<br>";
echo $oneWeekFromToday->format('Y-m-d') . "
<br>";
echo $twoWeeksFromToday->format('Y-m-d') . "
<br>";
输出:
2017-02-11
---
2017-02-11
2017-02-18
2017-02-25
在第二个示例中,我们得到了预期的日期.通过使用 DateTimeImmutable
而不是 DateTime
,我们可以防止意外的状态突变并防止潜在的错误.
In this second example, we get the dates we expected back. By using DateTimeImmutable
instead of DateTime
, we prevent accidental state mutations and prevent potential bugs.
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