我正在尝试通过 dropzone 将图像文件的特定 - 已经知道 - 位置 ID 发送到后端,该 ID 将上传到服务器上.虽然正在使用 formData.append()
,但我看到没有附加任何内容.而只是显示了这个FormData {}
".
I am trying to send through dropzone a specific -already known- position ID of an image file to the backend, which is going to be uploaded on the server.
Although the formData.append()
is being used, I see that nothing is appended.Instead just this "FormData {}
" shows up.
dropzoneObject.on("sending", function(file, xhr, formData){
var nameOfFile = $(file.previewElement).find(".dz-filename").text();
var positionOfFile = fpos;
//console.log("The file who's being sent is named: "+nameOfFile+" and its position id is: "+positionOfFile);
formData.append("fpos", fpos);
});
我希望在示例中看到 fpos=16;
I expect to see in example fpos=16;
不知道你的具体错误,但这里有一个简单的例子,说明如何使用 jQuery 使用 dropzone 发送附加数据并在后端使用 php 接收它.
Don't know about your particular error, but here is a simple example of how to send additional data with dropzone using jQuery and receiving it with php on the backend.
html:
<form id="myForm" class="dropzone"></form>
js:
Dropzone.autoDiscover = false;
$('.dropzone').dropzone ({
url: "upload.php",
init: function() {
this.on("sending", function(file, xhr, formData){
formData.append("fpos", 777)
}),
this.on("success", function(file, xhr){
alert(file.xhr.response);
})
},
});
成功事件只是为了演示如何访问服务器发送的响应:
The success event is only to demonstrate how to access the response send from the server:
php:
if(!empty($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest')
{
echo "RECEIVED ON SERVER:
";
echo "FILES:
";
print_r($_FILES);
echo "$_POST:
";
print_r($_POST);
}
php 只是将接收到的相同数据发送回客户端,只是为了显示可访问的位置.
The php simply sends back to client the same data received, just to show where is accessible.
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