我有这个作为 xml:
I have this as xml:
<root xmlns:event="http://www.webex.com/schemas/2002/06/service/event">
<event:event>
<event:sessionKey></event:sessionKey>
<event:sessionName>Learn QB in Minutes</event:sessionName>
<event:sessionType>9</event:sessionType>
<event:hostWebExID></event:hostWebExID>
<event:startDate>02/12/2009</event:startDate>
<event:endDate>02/12/2009</event:endDate>
<event:timeZoneID>11</event:timeZoneID>
<event:duration>30</event:duration>
<event:description></event:description>
<event:status>NOT_INPROGRESS</event:status>
<event:panelists></event:panelists>
<event:listStatus>PUBLIC</event:listStatus>
</event:event>
...
</root>
如何循环遍历所有 event:event 节点并显示,例如,所有 event:SessionKey 的?
How can I loop through all of the event:event nodes and display, for example, all of the event:SessionKey's?
这不起作用:
$xml = new SimpleXMLElement($r);
$xml->registerXPathNamespace('e', 'http://www.webex.com/schemas/2002/06/service/event');
foreach($xml->xpath('//e:event') as $event) {
var_export($event->xpath('//e:sessionKey'));
}
它确实可以在没有 registerXPathNamespace
和 xpath 查询中的完整命名空间前缀的情况下工作:
it does work without registerXPathNamespace
and the full namespace prefix in the xpath queries:
$xml = new SimpleXMLElement($r);
foreach($xml->xpath('//event:event') as $event) {
var_export($event->xpath('event:sessionKey'));
}
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