假设我的 XML 如下所示:
Say my XML looks like this:
<record>
<row name="title">this item</row>
<row name="url">this url</row>
</record>
现在我正在做这样的事情:
Now I'm doing something like this:
$xml = new DOMDocument();
$xml->load('xmlfile.xml');
echo $xml->getElementByTagName('row')->item(0)->attributes->getNamedItem('title')->nodeValue;
但这只是给了我:
注意:试图获取非对象 id 的属性
NOTICE: Trying to get property of non-object id
有人知道如何获取name"属性值为title"的节点值吗?
Does anybody know how to get the node value where the "name" attribute has value "title"?
试试:
$xml = new DOMDocument();
$xml->loadXml('
<record>
<row name="title">this item</row>
<row name="url">this url</row>
</record>
');
$xpath = new DomXpath($xml);
// traverse all results
foreach ($xpath->query('//row[@name="title"]') as $rowNode) {
echo $rowNode->nodeValue; // will be 'this item'
}
// Or access the first result directly
$rowNode = $xpath->query('//row[@name="title"][1]')->item(0);
if ($rowNode instanceof DomElement) {
echo $rowNode->nodeValue;
}
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