我有一个 JSON 字符串
I have a JSON string with me
{"name":"jack","school":"colorado state","city":"NJ","id":null}
我需要将它保存在数据库中.我怎么能这样做?
I need it to be saved in the Database. How could i do this ?
我的 PHP 代码(我只建立了与 MySQL 的连接,但我无法保存记录)
My PHP code (I have only establish the connection to MySQL, but i am unable to save the records)
<?php
// the MySQL Connection
mysql_connect("localhost", "username", "pwd") or die(mysql_error());
mysql_select_db("studentdatabase") or die(mysql_error());
// Insert statement
mysql_query("INSERT INTO student
(name, school,city) VALUES(------------------------- ) ") // (How to write this)
or die(mysql_error());
echo "Data Inserted or failed";
?>
我们将使用 json_decode
json_decode 文档
也一定要逃跑!下面是我的做法...
Also be sure to escape! here's how I would do it below...
/* create a connection */
$mysqli = new mysqli("localhost", "root", null, "yourDatabase");
/* check connection */
if (mysqli_connect_errno()) {
printf("Connect failed: %s
", mysqli_connect_error());
exit();
}
/* let's say we're grabbing this from an HTTP GET or HTTP POST variable called jsonGiven... */
$jsonString = $_REQUEST['jsonGiven'];
/* but for the sake of an example let's just set the string here */
$jsonString = '{"name":"jack","school":"colorado state","city":"NJ","id":null}
';
/* use json_decode to create an array from json */
$jsonArray = json_decode($jsonString, true);
/* create a prepared statement */
if ($stmt = $mysqli->prepare('INSERT INTO test131 (name, school, city, id) VALUES (?,?,?,?)')) {
/* bind parameters for markers */
$stmt->bind_param("ssss", $jsonArray['name'], $jsonArray['school'], $jsonArray['city'], $jsonArray['id']);
/* execute query */
$stmt->execute();
/* close statement */
$stmt->close();
}
/* close connection */
$mysqli->close();
希望这会有所帮助!
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