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      如何计算数组中连续的重复值?

      时间:2023-12-01

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              • 本文介绍了如何计算数组中连续的重复值?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!

                问题描述

                我有一个这样的数组:

                $arr = array(1, 1, 1, 2, 2, 3, 3, 1, 1, 2, 2, 3);
                

                我找到了函数 array_count_values(),但它会将所有相同的值分组并计算出现次数,而不考虑连续序列中的中断.

                I found the function array_count_values(), but it will group all of the same values and count the occurrences without respecting breaks in the consecutive sequences.

                $result[1] = 5
                $result[2] = 4
                $result[3] = 3
                

                如何对每组连续值进行分组并计算每个序列的长度?请注意,数字 123 有两组序列.

                How can I group each set of consecutive values and count the length of each sequence? Notice there are two sets of sequences for the numbers 1, 2, and 3.

                我期望生成的数据需要类似于:

                The data that I expect to generate needs to resemble this:

                [1] = 3;
                [2] = 2;
                [3] = 2;
                [1] = 2;
                [2] = 2;
                [3] = 1;
                

                推荐答案

                只需手动即可:

                $arr = array(1,1,1,2,2,3,3,1,1,2,2,3);
                
                $result = array();
                $prev_value = array('value' => null, 'amount' => null);
                
                foreach ($arr as $val) {
                    if ($prev_value['value'] != $val) {
                        unset($prev_value);
                        $prev_value = array('value' => $val, 'amount' => 0);
                        $result[] =& $prev_value;
                    }
                
                    $prev_value['amount']++;
                }
                
                var_dump($result);
                

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