根据这个答案 "Android 使用 HTTP 多部分表单数据将视频上传到远程服务器"我完成所有步骤.p>
但我不知道如何为服务器端编码！我的意思是一个 PHP 简单的页面，为我最可靠的敌人上传服务.
另一个问题是:YOUR_URL(以下代码段的第 3 行)必须是那个 PHP 页面的地址?
private void uploadVideo(String videoPath) throws ParseException, IOException {HttpClient httpclient = new DefaultHttpClient();HttpPost httppost = 新的 HttpPost(YOUR_URL);FileBody filebodyVideo = new FileBody(new File(videoPath));StringBody title = new StringBody("文件名:" + videoPath);StringBody description = new StringBody("这是视频的描述");MultipartEntity reqEntity = new MultipartEntity();reqEntity.addPart("videoFile", filebodyVideo);reqEntity.addPart("标题", 标题);reqEntity.addPart("描述", 描述);httppost.setEntity(reqEntity);//调试System.out.println("执行请求" + httppost.getRequestLine());HttpResponse 响应 = httpclient.execute( httppost );HttpEntity resEntity = response.getEntity();//调试System.out.println(response.getStatusLine());如果(resEntity！= null){System.out.println(EntityUtils.toString(resEntity));}//万一如果(resEntity！= null){resEntity.consumeContent();}//万一httpclient.getConnectionManager().shutdown();}这段代码运行正常，我应该使用的 PHP 代码就这么简单:
注意 videoFile 必须完全匹配
reqEntity.addPart("videoFile", filebodyVideo);
您可能面临的最重要问题是服务器配置中 post_max_size 和 upload_max_filesize 的默认值！由于默认值太小，当您尝试上传大文件时，PHP 脚本返回:"upload_fail_php_file"，没有错误或异常抛出.所以请记住将这些值设置得足够大...
享受编码.
According this answer "Android upload video to remote server using HTTP multipart form data" I do all steps.
But I don't know how I code for server side! I mean a PHP simple page that serve my reauest foe upload.
And another question is that : YOUR_URL (3rd line of following snippet) must be address of that PHP page?
private void uploadVideo(String videoPath) throws ParseException, IOException {
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(YOUR_URL);
FileBody filebodyVideo = new FileBody(new File(videoPath));
StringBody title = new StringBody("Filename: " + videoPath);
StringBody description = new StringBody("This is a description of the video");
MultipartEntity reqEntity = new MultipartEntity();
reqEntity.addPart("videoFile", filebodyVideo);
reqEntity.addPart("title", title);
reqEntity.addPart("description", description);
httppost.setEntity(reqEntity);
// DEBUG
System.out.println( "executing request " + httppost.getRequestLine( ) );
HttpResponse response = httpclient.execute( httppost );
HttpEntity resEntity = response.getEntity( );
// DEBUG
System.out.println( response.getStatusLine( ) );
if (resEntity != null) {
System.out.println( EntityUtils.toString( resEntity ) );
} // end if
if (resEntity != null) {
resEntity.consumeContent( );
} // end if
httpclient.getConnectionManager( ).shutdown( );
}
This code worked properly and PHP code I should use is as simple as this:
<?php
$file_path = "uploads/";
$file_path = $file_path . basename( $_FILES['videoFile']['name']);
if(move_uploaded_file($_FILES['videoFile']['tmp_name'], $file_path)) {
echo "success";
} else{
echo "upload_fail_php_file";
}
?>
NOTE that videoFile must match exactly with
reqEntity.addPart("videoFile", filebodyVideo);
And the MOST Important problem you probably face to, is default value of post_max_size and upload_max_filesize in the server config! As default is too small and when you try to upload large files, the PHP script return : "upload_fail_php_file" with no error or exception throwing. So remember to set these values as big as enough...
Enjoy coding.
这篇关于Android:使用 MultipartEntity 上传大文件的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持跟版网！