我有一个运行在 linux 机器上的 Intranet,它通过 PHP 使用 LDAP 对 Windows 机器上的 Active Directory 进行身份验证.
I have an intranet running on a linux box, which authenticates against Active Directory on a Windows box, using LDAP through PHP.
我可以使用 LDAP 从 AD 检索用户的条目并从 php 数组访问上次登录日期,例如:
I can retrieve a user's entry from AD using LDAP and access the last login date from the php array eg:
echo $adAccount['lastlogontimestamp'][0]; // returns something like 129802528752492619
如果这是一个 Unix 时间戳,我将使用以下 PHP 代码转换为人类可读的日期:
If this was a Unix timestamp I would use the following PHP code to convert to a human readable date:
date("d-m-Y H:i:s", $lastlogontimestamp);
然而,这行不通.有谁知道我如何实现这一点,或者是否可以从 Linux 机器上实现?
However, this does not work. Does anyone know how I can achieve this or indeed if it is possible to do so from a Linux box?
根据 this,您拥有的 Windows 时间戳是自 1601 年 1 月 1 日以来的 100 ns 数.因此,您可以使用以下公式将其转换为 unix 时间戳:
According to this, the windows timestamp you have there is the number of 100-ns since Jan 1st 1601. Therefore, you could just convert it to a unix timestamp using the following formula:
tUnix = tWindow/(10*1000*1000)-11644473600;
您除以 10*1000*1000
转换为自 1601 年 1 月 1 日以来的秒数,然后您将 11644473600
打折,这是 1601 年 1 月和 1970 年 1 月之间的秒数(Unix 时间).
You divide by 10*1000*1000
to convert to seconds since Jan 1st 1601 and then you discount 11644473600
which is the number of seconds between Jan 1601 and Jan 1970 (unix time).
所以在 PHP 中:
date("d-m-Y H:i:s", $lastlogontimestamp/10000000-11644473600);
有趣的是,我得到的偏移量与 Baba 不同.我用 Java 得到了我的:
Interestingly, I got a different offset than Baba. I got mine with Java:
Calendar date1 = Calendar.getInstance(); date1.set(1601, 1, 1);
Calendar date2 = Calendar.getInstance(); date2.set(1970, 1, 1);
long dt = date2.getTimeInMillis() - date1.getTimeInMillis();
System.out.println(String.format("%f", dt / 1000.0)); // prints "11644473600.000000"
根据此 SO:将 Unix/Linux 时间转换为 Windows 时间的方法我的偏移量是正确的.
According to this SO: Ways to Convert Unix/Linux time to Windows time my offset is correct.
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