我有一个由
元素和一个 class="active"
元素组成的简单菜单,用于标记当前页面.$_get[]
传递一个变量,通过 url 选择特定页面:?pg=PAGE
.
I have a simple menu made of <ul><li>
elements and a class="active"
in place to mark the current page. A variable is passed by $_get[]
to select the specific page by url: ?pg=PAGE
.
我对 php 还很陌生,还在学习中.这工作得很好,但我觉得应该有一种更简单、更短的方法.
I am fairly new to php and still learning. This works just fine, but i feel there ought to be a simpler and shorter way.
<ul class="nav">
<li <?php if ($_GET['pg'] == "PAGE1") { echo "class="active""; } ?>><a href="?pg=PAGE1">FIRST PAGE</a></li>
<li <?php if ($_GET['pg'] == "PAGE2") { echo "class="active""; } ?>><a href="?pg=PAGE2">SECOND PAGE</a></li>
</ul>
<?php
$pages = array(
'PAGE1' => 'FIRST PAGE',
'PAGE2' => 'SECOND PAGE');
?>
<ul class="nav">
<?php foreach ($pages as $pageId => $pageTitle): ?>
<li <?=(($_GET['pg'] == $pageId) ? 'class="active"' : '')?>><a href="?pg=<?=$pageId?>"><?=$pageTitle?></a></li>
<?php endforeach; ?>
</ul>
http://php.net/manual/en/control-structures.foreach.php
不要重复自己——两个 li
-s 非常相似,唯一的区别是页面 ID 和标题.一旦您拥有两个以上的页面,这种方法将非常有用.
Don't repeat yourself -- both li
-s are very similar, the only difference is in page ID and title. This approach will really help once you have more than two pages.
尽量将 PHP 和 HTML 分开——一旦您决定将它们保存在单独的文件中(有时您会这样做),这将使您的生活更轻松.
Try to keep PHP and HTML as separate as possible -- this will make your life easier once you decide to keep them in separate files (and you will sometimes).
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