我必须在 symfony 2 的学说 ORM 中使用 SUBSTRING_INDEX
函数.我该怎么做?现在在查询中使用它会给我未定义的函数错误:
I have to use SUBSTRING_INDEX
function in doctrine ORM in symfony 2. How can I do this? Right now using it inside the query gives me undefined function error:
[Syntax Error] line 0, col 299: Error: Expected known function, got 'SUBSTRING_INDEX'
我使用这个函数来获取第一个数字,例如:
I use this function to get the first number from, for example:
11.48.205.1
我该如何解决这个问题?
How can I solve this?
这里是代表 SUBSTRING_INDEX 函数的类(不要忘记更新命名空间).
Here is class that represent SUBSTRING_INDEX function (don't forget to update namespace).
<?php
namespace SadFunctions;
use DoctrineORMQueryASTFunctionsFunctionNode;
use DoctrineORMQueryLexer;
use DoctrineORMQuerySqlWalker;
use DoctrineORMQueryParser;
/**
* "SUBSTRING_INDEX" "(" ArithmeticPrimary "," ArithmeticPrimary "," ArithmeticPrimary ")"
*
* @author Andrey Stepanov <stepashka@gmail.com>
*/
class SubstringIndexFunction extends FunctionNode
{
public $str = null;
public $delim = null;
public $count = null;
/**
* @override
*/
public function getSql(SqlWalker $sqlWalker)
{
return 'SUBSTRING_INDEX(' .
$this->str->dispatch($sqlWalker) . ', ' .
$this->delim->dispatch($sqlWalker) . ', ' .
$this->count->dispatch($sqlWalker) .
')';
}
/**
* @override
*/
public function parse(Parser $parser)
{
$parser->match(Lexer::T_IDENTIFIER);
$parser->match(Lexer::T_OPEN_PARENTHESIS);
$this->str = $parser->ArithmeticPrimary();
$parser->match(Lexer::T_COMMA);
$this->delim = $parser->ArithmeticPrimary();
$parser->match(Lexer::T_COMMA);
$this->count = $parser->ArithmeticPrimary();
$parser->match(Lexer::T_CLOSE_PARENTHESIS);
}
}
在创建实体管理器之前需要先注册:
You need to register it before creating entity manager:
$config->addCustomStringFunction('SUBSTRING_INDEX', 'SadFunctionsSubstringIndexFunction');
/* ... */
$entityManager = EntityManager::create($conn, $config);
完成后,您将获得以下结果:
After you do it you'll get the following results:
echo $entityManager->createQuery("SELECT p FROM SadSchemaAbstractPageAny as p WHERE SUBSTRING_INDEX(p.name,'a',1) = 'P'")->getSQL();
// Output: SELECT p0_.id AS id_0, p0_.name AS name_1, p0_.type AS type_2 FROM page p0_ WHERE (SUBSTRING_INDEX(p0_.name, 'a', 1) = 'P')
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