我想在视图中显示数据库中的最后一个登录ID > _form.php 文件.我在 _form.php 文件中制作了这样的代码
<?php echo $form->labelEx($model,'id');?><?php echo Yii::app()->db->getLastInsertId('Form');?><?php echo $form->error($model,'id');?>
这里的表格是表格和型号名称.但我仍然得到 ID:0
.哪里出错了?
Pekka 的回答对普通有好处.但是如果你想在 Yii Framework
中做那个动作,试试这个:
$myModel = 新的 $model;$模型 ->保存(假);echo $model->primaryKey;//打印最后一个 id.
或者你也可以试试这个作为通用解决方案:
Yii::app()->db->getLastInsertID();
最后,我建议您查看这个
I want to show the last login id from the database in view > _form.php file.I have made the code in _form.php file like this
<div class="row">
<?php echo $form->labelEx($model,'id'); ?>
<?php echo Yii::app()->db->getLastInsertId('Form');?>
<?php echo $form->error($model,'id'); ?>
</div>
Here Form is the table and the model name.But Still I am getting ID:0
.Where is the wrong part?
Pekka's answer is good for common. But if you want to do that action in Yii Framework
, try this:
$myModel = new $model;
$model -> savel(false);
echo $model->primaryKey; // Prints the last id.
Or you may try this too for general solution:
Yii::app()->db->getLastInsertID();
Finally, I suggest you to check out this
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