我有两个相关数据的表,我想从一个表中选择另一个表中不存在的所有记录,加上相关表上的一些其他条件,如下(123仅用于说明目的):
I have two tables with related data, and I want to select all the records from one table which do not exist in the other table, plus some other criteria on the related table, as follows (123 is just for illustration purposes):
TABLE A
ID
SOMETHING
TABLE B
TABLE_A_ID
TABLE_C_ID
SOMETHING
我的查询,直接针对数据运行,如下
My query, run directly against the data, would be as follows
SELECT A.SOMETHING
FROM A
WHERE A.ID NOT IN (
SELECT
B.TABLE_A_ID AS ID
FROM B
WHERE TABLE_C_ID = 123
);
我如何在 Zend 中运行它?
How can I run this in Zend?
可以直接运行sql,使用$db->query()
;你的将是:
You can run direct sql, using $db->query()
; yours would simply be:
$results = $db->query("SELECT A.SOMETHING
FROM A
WHERE A.ID NOT IN (
SELECT
B.TABLE_A_ID AS ID
FROM B
WHERE TABLE_C_ID = ?
)", $id);
编辑:要回答这是否可以用对象表示法来完成,是:
EDIT: To answer whether this can be done with the object notation, yes:
$sub_select = $zdb->select()
->from("b", array("table_a_id AS id"))
->where("table_c_id = ?", 'a');
$select = $zdb->select()
->from("a", array("something"))
->where("id NOT IN ?", $sub_select);
print $select->__toString();
给予
SELECT `a`.`something` FROM `a`
WHERE (id NOT IN
(SELECT `b`.`table_a_id` AS `id` FROM `b` WHERE (table_c_id = 'a')))
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