我想将查询的结果提取到一个类中(到一个类的实例数组中).但我收到以下错误消息:致命错误:在...中找不到类类别"这是我的数据库管理器类中涉及的两个函数的代码:
I want to fetch the result of a query into a class (into an array of instances of a class). But I get the following error message: Fatal error: Class 'Category' not found in ... This is the code of the two functions in my database manager class that are involved:
public function prepareStatement($_Statement)
{
$this->preparedStmt = $this->pdo->prepare($_Statement);
if($this->preparedStmt === FALSE)
throw new PreparedStmtException ("Fehler: Statement konnte nicht prepared werden.");
else
return TRUE;
}
public function execute($_Params = array(), $_FetchMode = NULL, $_Class = NULL)
{
# Cancel execution if no statement prepared
if($this->preparedStmt === null)
throw new PreparedStmtException ("Fehler: Statement wurde vor execute nicht prepared.");
try
{
# Execute PDO call with params
$this->preparedStmt->execute($_Params);
# If no data is returned throw NoDataException
if($this->preparedStmt->columnCount() == 0)
throw new NoDataException;
// else
// Determine which fetch mode should be called, if NULL or something != 1 || != 0 just call
// fetchAll without params
if ($_FetchMode == 1)
$result = $this->preparedStmt->fetchAll(PDO::FETCH_ASSOC);
else if ($_FetchMode == 2)
$result = $this->preparedStmt->fetchAll(PDO::FETCH_CLASS, $_Class);
else
$result = $this->preparedStmt->fetchAll();
}
catch (PDOException $e)
{
# Errormanagement --> Message im live Betrieb rausnehmen
echo '<div style="color: red;">'.$e->getMessage().'</div>';
$result = FALSE;
}
// If result is null throw Instance Exception, if result emtpy throw NoDataException
if ($result == null)
throw new InstanceException;
else if (empty($result))
throw new NoDataException;
return $result;
}
这是一个类中的测试函数来调用它们:
This is a test function in a class to call them:
public function test ()
{
$stmt = "SELECT * FROM tx_exhibition_category WHERE uid = 1 OR uid = 2";
$this->mysql->prepareStatement($stmt);
return $this->mysql->execute (array(), 2, "Category");
}
这就是我调用测试函数的方式:
This is how i call test function:
$comment = CommentQuery::getInstance();
$result = $comment->test();
var_dump($result); // should be an array with instances of Category
这是它应该被提取到的类:
And this is the class where it should be fetched into:
class Category {
private $id;
private $name;
private $projectId;
// getter and setter...
}
一些附加信息:
有什么想法吗?
如果您的 Category
类在命名空间中,您需要将完全限定的类名传入 fetchAll
.
If your Category
class is in a namespace, you'll need to pass in a fully qualified class name into fetchAll
.
现在,PDO 正在尝试获取根命名空间中的 Category
类.它不存在.你需要告诉 PDO 关于命名空间:
Right now, PDO is trying to fetch into the class Category
in the root namespace. It doesn't exist. You need to tell PDO about the namespace:
$stm->fetchAll(PDO::FETCH_CLASS, 'Vendor\Package\Category');
或者使用 __NAMESPACE__
常量,如果这样更容易(并且正确):
Or use a __NAMESPACE__
constant if that makes it easier (and is correct):
$stm->fetchAll(PDO::FETCH_CLASS, __NAMESPACE__ . '\Category');
或者,更好的是,使用 PHP 5.5+ 的 ::class
常量来获取完全限定的类名.
Or, even better, use PHP 5.5+'s ::class
constant to ge the fully qualified class name.
use AcmePackageCategory;
$stm->fetchAll(PDO::FETCH_CLASS, Category::class);
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