我正在使用一个可以完美返回值的查询,但它向集合中添加了键号.如何删除索引号?
I am using a query that returns value perfectly but it adds key number to the collection. How can I remove the index number?
这是检索到的数据
{
"data": {
"0": {
"id": 135,
"conversation_id": 11,
"last_sender": null,
"last_reciever": {
"id": 54,
"userName": "Sadek",
"profilePic": "Nir7zgorNT2dmwcXJdhNK3ZmPAltmkEnj0SXDCDC.png",
"firstName": "Sadek",
"lastName": "Hossain"
},
"msg": "hello guys how are you",
"attachment": null,
"deleted": 0,
"seen": 0,
"created_at": "2017-10-17 16:56:41",
"updated_at": "2017-10-17 16:56:41"
},
"2": {
"id": 133,
"conversation_id": 13,
"last_sender": null,
"last_reciever": {
"id": 55,
"userName": "buyer",
"profilePic": "pRBDBFJW55baSnF560Ajid8jTgPo5kmg4i5LMhPG.jpeg",
"firstName": "Matti",
"lastName": "Rames"
},
"msg": "second message 2 to user second",
"attachment": null,
"deleted": 0,
"seen": 0,
"created_at": "2017-10-17 15:43:14",
"updated_at": "2017-10-17 15:43:14"
}
}
}
但我想返回这样的结果
{
"data": [
{
"id": 133,
"conversation_id": 13,
"last_sender": null,
"last_reciever": {
"id": 55,
"userName": "buyer",
"profilePic": "pRBDBFJW55baSnF560Ajid8jTgPo5kmg4i5LMhPG.jpeg",
"firstName": "Matti",
"lastName": "Rames"
},
"msg": "second message 2 to user second",
"attachment": null,
"deleted": 0,
"seen": 0,
"created_at": "2017-10-17 15:43:14",
"updated_at": "2017-10-17 15:43:14"
},
{
"id": 135,
"conversation_id": 11,
"last_sender": null,
"last_reciever": {
"id": 54,
"userName": "Sadek",
"profilePic": "Nir7zgorNT2dmwcXJdhNK3ZmPAltmkEnj0SXDCDC.png",
"firstName": "Sadek",
"lastName": "Hossain"
},
"msg": "hello guys how are you",
"attachment": null,
"deleted": 0,
"seen": 0,
"created_at": "2017-10-17 16:56:41",
"updated_at": "2017-10-17 16:56:41"
}
]
}
我的查询是(我认为重要的最后几部分)
My query is (last few parts that I think is important)
->orderBy('created_at', 'desc')
->get()
->unique('conversation_id');
请告诉我如何从该集合中删除0"和2".
Please tell me how can I remove "0" and "2" from this collection.
必须手动操作
$users=AppUser::get()->toArray(); // your query here
$data['data']=[];
foreach($users as $user ){
$data['data'][]=$user;
}
$k=json_encode($data); dd($k);
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