我有这个代码:
$sql = new PDO('mysql:host=localhost;dbname=b', 'root', 'root');
$f = $sql->query('select * from user');
$sql->setFetchMode(PDO::FETCH_ASSOC);
while($row = $f->fetch()){
print_r($row);
}
输出是
Array
(
[id] => 1
[name] => turki
[mail] => ablaf
[pass] => 144
)
Array
(
[id] => 2
[name] => wrfwer
[mail] => fwerf
[pass] => werf
)
这就是我真正想要的.但是如果我这样做
And that's what I really want. But if I do this
<?php
$sql = new PDO('mysql:host=localhost;dbname=b', 'root', 'root');
$f = $sql->query('select * from user');
$f->setFetchMode(PDO::FETCH_ASSOC);
print_r($f->fetch());
?>
输出是
Array
(
[id] => 1
[name] => turki
[mail] => ablaf
[pass] => 144
)
它有一个结果,但我在表中有两行;这是为什么?
It has one result, but I have two rows in the table; why is that?
应该使用 Fetch 来显示数据库结果中的下一行.
Fetch should be used to display the next row from the database result.
要获取所有行,您应该使用 fetchAll();
To get all rows, you should use fetchAll();
将您的示例更改为:
<?php
$sql = new PDO('mysql:host=localhost;dbname=b', 'root', 'root');
$f = $sql->query('select * from user');
$f->setFetchMode(PDO::FETCH_ASSOC);
print_r($f->fetchAll());
?>
或者如果你想使用 PDOStatement::fetch 来
or if you want use PDOStatement::fetch to
<?php
$sql = new PDO('mysql:host=localhost;dbname=b', 'root', 'root');
$f = $sql->query('select * from user');
while($row = $sth->fetch(PDO::FETCH_ASSOC))
{
print_r($row);
}
?>
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