我收到警告:
警告:mysqli_query() 期望参数 1 是 mysqli,在第 6 行的 (...) 中给出的字符串
Warning: mysqli_query() expects parameter 1 to be mysqli, string given in (...) on line 6
我的代码在这里:
<?php
require_once 'conn.php';
$sql = "SELECT user_id, access_lvl, name FROM cms_users ";
$result = mysqli_query($sql, $conn);
这与您错误地将参数传递给 mysqli_query()
时的错误状态完全一样.假设 $conn
是您在某个时候由 new mysqli()
生成的 mysqli 连接,它应该是:
It's exactly as the error states as you're passing arguments to mysqli_query()
incorrectly. Assuming $conn
is your mysqli connection generated at some point by new mysqli()
it should be:
$result = mysqli_query( $conn,$sql) or trigger_error(mysqli_error($conn)));
你调用它的方式是传递一个字符串,$sql
作为第一个参数.
The way you were calling it you were passing a string, $sql
as the first argument.
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