我有一段这样的代码:
$conn = new mysqli($host, $username, $passwd, $dbname);
...
$stmt = $conn->prepare('SELECT ...');
$stmt->bind_param(...);
$stmt->execute();
$stmt->bind_result(...);
while($stmt->fetch())
{
// do something here
}
$stmt->close();
...
// do something more here that has absolutely nothing to do with $stmt
这很好用.我得到了预期的结果,没有错误或任何不应该发生的事情.
This works perfectly fine. I get the results I expected, there are no errors or anything that is not supposed to happen.
但是如果我将断点(Xdebug 2.2.5/2.2.6/2.2.8/2.3.2 和 PHP 5.5.3/5.5.15/5.6.0/5.6.6/5.6.10)设置为一行之后 $stmt->close();
,我收到很多警告,比如
But if I set a break point (Xdebug 2.2.5 / 2.2.6 / 2.2.8 / 2.3.2 and PHP 5.5.3 / 5.5.15 / 5.6.0 / 5.6.6 / 5.6.10) to a line after $stmt->close();
, I get many warnings like
尚未允许访问属性
或
无法获取 mysqli_stmt
Couldn't fetch mysqli_stmt
我以为我错过了关闭另一个 mysqli 语句,但我得到了所有结果.我的代码似乎没有问题...
I thought I missed to close another mysqli statement, but I get all results. There seems to be just no problem in my code...
有没有办法摆脱这种错误警告?
Is there a way to get rid of this wrong warnings?
更新:这个问题在 PHP 7.0.1/Xdebug 2.4.0 RC3 中仍然存在.
Update: This problem still exist in PHP 7.0.1 / Xdebug 2.4.0 RC3.
有一些类似的问题报告
http://bugs.xdebug.org/view.php?id=900
https://bugs.php.net/bug.php?id=60778
摆脱此消息的一种方法是添加
One way to get rid of this messages is to add
unset($stmt);
在关闭语句之后和断点之前.如果这没有帮助,您还应该添加
after closing the statement and before the breakpoint. If this does not help, you should also add
unset($connection);
在@Martin 在评论中提到关闭连接之后.
after closing the connection as mentioned by @Martin in the comments.
这本身并不能解决问题,而是让您继续工作,直到这可能会在一段时间内得到解决.
This does not solve the problem itself, but let you go on with your work until this may be fixed some time.
编辑:现在还有一个报告的问题一个> :)
编辑:据报道,这似乎是 MySQLi 驱动程序中的一个错误 此处.
EDIT: This seems to be a bug in the MySQLi driver as reported here.
EDIT:如果您使用 PDO,看起来这个错误不会出现.所以这可能是切换到 PDO 的另一个原因.
EDIT: Looks like this bug does not appear if you use PDO. So this is maybe an other reason to switch to PDO.
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