从服务器到服务器的http传输文件

If you take a look at the list of options you can set with curl_setopt, you'll see this one : CURLOPT_POSTFIELDS (quoting) :

要在 HTTPPOST"中发布的完整数据手术.
要发布文件，在文件名前面加上@ 并使用完整路径.
这可以是作为 urlencoded 字符串传递，如'para1=val1&para2=val2&...' 或作为以字段名称为键的数组和字段数据作为值.
如果值是一个数组，Content-Type 标头将设置为 multipart/form-data.

The full data to post in a HTTP "POST" operation.
To post a file, prepend a filename with @ and use the full path.
This can either be passed as a urlencoded string like 'para1=val1&para2=val2&...' or as an array with the field name as key and field data as value.
If value is an array, the Content-Type header will be set to multipart/form-data.

未经测试，但我认为这样的事情应该可以解决问题 - 或者至少
帮助您入门:

Not tested,but I suppose that something like this should do the trick -- or at least
help you get started :

$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, "http://www.example.com/your-destination-script.php");
curl_setopt($ch, CURLOPT_HEADER, false);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_POSTFIELDS, array(
        'file' => '@/..../file.jpg',
         // you'll have to change the name, here, I suppose
         // some other fields ?
));
$result = curl_exec($ch);
curl_close($ch);

基本上，你:

• 正在使用 curl
• 必须设置目标网址
• 表示你希望curl_exec返回结果，而不是输出它
• 正在使用 POST，而不是 GET
• 正在发布一些数据，包括一个文件 -- 请注意文件路径前的 @.

• are using curl
• have to set the destination URL
• indicate you want curl_exec to return the result, and not output it
• are using POST, and not GET
• are posting some data, including a file -- note the @ before the file's path.

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