在 UITabBar.h 中,一个属性签名的副本
In UITabBar.h, a propery signed copy
@property(nonatomic,copy) NSArray *items;//获取/设置可见
@property(nonatomic,copy) NSArray *items; // get/set visible
这是一个数组复制"是什么意思?复制 NSArray 容器 obj?复制每个 obj NSArray 包含的内容?什么的.
It's a array And what "copy" means? copy NSArray container obj? copy every obj NSArray contains? or something.
UITabBar* testBar = [[UITabBar alloc] init];
UITabBarItem* item = [[UITabBarItem alloc] init];
NSArray* array = [[NSArray alloc] initWithObjects:item, nil];
NSLog(@"bar:%p,%d", testBar, testBar.retainCount);
NSLog(@"item:%p,%d", item, item.retainCount);
NSLog(@"array:%p,%d", array, array.retainCount);
testBar.items = array;
NSLog(@"that item:%p,%d", [testBar.items lastObject], [[testBar.items lastObject] retainCount]);
NSLog(@"testBar.items:%p,%d", testBar.items, testBar.items.retainCount);
栏:0x96a9750,1
bar:0x96a9750,1
项目:0x96aa230,2
item:0x96aa230,2
数组:0x96aa280,1
array:0x96aa280,1
那个项目:0x96aa230,2
that item:0x96aa230,2
testBar.items:0x96aa280,6
testBar.items:0x96aa280,6
为什么容器数组和数组中的obj都没有被复制"?
why neither container array nor obj in array has been "copied"?
这种情况下没有复制的原因是NSArray
是不可变的.您不需要复制它来防止对数组进行更改,因为无法进行此类更改;保留相同的不可变数组就足够了.
The reason the copy has not been made in this case is that NSArray
is immutable. You do not need to make a copy of it to guard against changes to the array, because such changes cannot be made; it is sufficient to retain the same immutable array.
如果你用 NSMutableArray
尝试这个实验,你会得到不同的结果.
If you try this experiment with NSMutableArray
, you will get a different result.
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