Firebase 实例 ID:在 21.0.0 中弃用 getId()

问题描述

随着最近发布的 FirebaseInstanceId 和 FirebaseCloudMessaging (21.0.0) Firebase 已弃用 iid 包以及 getToken() 和 >getId() 方法现已弃用.

With the recent release of FirebaseInstanceId and FirebaseCloudMessaging (21.0.0) Firebase has deprecated iid package and both getToken() and getId() methods are now deprecated.

根据 Firebase 发行说明 方法 getToken() 移至 FirebaseMessaging

之前:

FirebaseInstanceId.getInstance().getToken()

之后:

FirebaseMessaging.getInstance().getToken()

使用 fcmToken，但要检索 instance id，FirebaseMessaging 和 FirebaseInstanceId 中没有可用的方法.

Which gives use the fcmToken, but to retrieve instance id, there's no method available in FirebaseMessaging nor FirebaseInstanceId.

那么，instance_id是否被认为是无用的id，不应该再使用了?还是有替代品?

So, Is instance_id considered a useless id and should no longer be used? or is there a replacement for this?

推荐答案

FirebaseInstanceId 类已弃用，获取令牌使用 FirebaseMessagingClass.可以使用以下代码生成令牌:

FirebaseInstanceId class is deprecated, to get token use FirebaseMessagingClass. The token can be generated using the following code:

FirebaseMessaging.getInstance().getToken()
.addOnCompleteListener(new OnCompleteListener<String>() {
    @Override
    public void onComplete(@NonNull Task<String> task) {
      if (!task.isSuccessful()) {
        Log.w(TAG, "Fetching FCM registration token failed", task.getException());
        return;
      }

      // Get new FCM registration token
      String token = task.getResult();

      // Log and toast
      String msg = getString(R.string.msg_token_fmt, token);
      Log.d(TAG, msg);
      Toast.makeText(MainActivity.this, msg, Toast.LENGTH_SHORT).show();
    }
});

关于Firebase InstanceId，官方文档是这样说的:

Regarding the Firebase InstanceId, this is what the official document says:

公共任务getInstanceId()->此方法已弃用.对于实例标识符，请改用 FirebaseInstallations.getId().对于 FCM 注册令牌，请改用 FirebaseMessaging.getToken().

public Task getInstanceId () -> This method is deprecated. For an instance identifier, use FirebaseInstallations.getId() instead. For an FCM registration token, use FirebaseMessaging.getToken() instead.

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