我的应用中有一些代码向我发送未捕获异常的堆栈跟踪.
I have some code in my app that sends me the stack trace of uncaught exceptions.
"0 CoreFoundation 0x3ad073ff <redacted> + 186",
"1 libobjc.A.dylib 0x39412963 objc_exception_throw + 30",
"2 CoreFoundation 0x3ad0729d <redacted> + 0",
"3 Foundation 0x39f3b7b3 <redacted> + 90",
"4 UIKit 0x34a3ae29 <redacted> + 4184",
"5 MyApp 0x0001feab -[MAMyClassA firstMethod:withParameter1:andParameter2:] + 374",
"6 MyApp 0x000f76b5 -[MAMyClassB secondMethod:withParameter1:andParameter2:] + 164",
"7 UIKit 0x34bd0fe1 <redacted> + 84",
"8 UIKit 0x34af2047 <redacted> + 70",
"9 UIKit 0x34af1ffb <redacted> + 30",
"10 UIKit 0x34af1fd5 <redacted> + 44",
...
如您所见，Apple 的大部分方法都替换为 <redacted>.我已经能够使用 nm 从 Apple 库中提取符号及其对应的基地址，但地址不匹配.他们落后 1 点.
As you can see, most of Apple's methods are replaced with <redacted>. I have been able to extract the symbols and their corresponding base addresses from Apple's libraries using nm, but the addresses do not match. They are off by 1.
我已经按照此处的说明计算了地址:iOS 崩溃报告:atos 没有按预期工作.
I have calculated the address as explained here: iOS crash reports: atos not working as expected.
Symbol address = (base address of framework) - (base address of symbol from crash report) + (virtual memory slide [vmaddr]).
例如，我得到的是 0xC2345，但 nm 返回的实际符号地址是 0xC2344.我知道这是正确的符号.我已经在不同的崩溃报告中使用不同框架(UIKit、Foundation、CoreFoundation 等)中的不同地址进行了尝试，结果是相同的:该值始终为 1.我必须从我得到的值中减去 1崩溃报告以获取 nm 提供的正确"地址.
For example, I'm getting 0xC2345, but the actual symbol address returned by nm is 0xC2344. I know that this is the right symbol. I have tried this with different addresses in different frameworks (UIKit, Foundation, CoreFoundation, etc.) in different crash reports and the result is the same: the value is always off by 1. I have to subtract 1 from what I get in the crash report to get the "right" address as provided by nm.
当我输入这个问题时，我发现:Wrong methodotool for armv7的实现地址?.
As I am typing this question, I found this: Wrong method implementation address from otool for armv7?.
这是否意味着每次我要查找地址时都必须执行以下逻辑?
Does that mean that every time I have an address to look up I have to perform the following logic?
if ((symbol address) mod 2 == 1) {
// This is a thumb instruction so it may be 2 or four bytes
Subtract 1 from the symbol address and then use it to lookup the symbol.
}
else {
// This is a standard 4-byte ARM instruction.
Perform symbol lookup with the address as is.
}
提前感谢您的任何帮助或指导.
Thanks in advance for any help or direction.
PC中的LSB显示当前的执行模式.如果该位为 0，则为 ARM，如果设置为 1，则在 Thumb 模式下执行.所以是的，你会得到这样的真实地址:
The LSB in the PC shows the current execution-mode. If the bit is 0 then it's ARM, if it's set to 1 then the execution is done in Thumb-Mode. So yes, you'll get the real address like this:
real_address = address & ~1;
而当前的执行模式是这样的:
And the current execution mode like this:
is_thumb_mode = address & 1;
如今的大多数代码都将被编译为 Thumb-2，因为它只有少数区域缺少真正的"ARM 代码，并且通常可以节省大约 30% 的代码大小.
Most code these days will be compiled to Thumb-2 as it has only a few areas where it lacks behind "real" ARM-code and usually saves about 30% in code size.
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