我有以下问题:
我有一个现有的 ListFragment
,但我想将其显示为对话框.
I have an exisiting ListFragment
, but I would like to display this as a dialog.
我的第一种方法是创建一个 DialogFragment
,它必须在其中 ListFragment
,但目前似乎无法将片段放入片段中.
My first approach was to create a DialogFragment
which has to ListFragment
inside of it, but appearently it is currently not possible to put fragments in fragments.
扩展 DialogFragment
而不是 ListFragment
也是不可能的,因为大量使用了 ListFragment
方法.
Extending DialogFragment
instead of ListFragment
is also not possible, because of the heavy use of ListFragment
methods.
有没有简单的方法可以做到这一点?
Is there an easy way to do this?
对我有用的是
1) 在 DialogFragment 的 xml 布局中调用,比如说 DialogFragmentwWithListFragment 指定 ListFragment 类
例如.dialog_fragment_with_list_fragment.xml:
What works for me is
1) in xml layout for your DialogFragment called, let's say, DialogFragmentwWithListFragment specify ListFragment class
E.g. dialog_fragment_with_list_fragment.xml :
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent">
<fragment
android:id="@+id/flContent"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:padding = "10dp"
class="com.xxx.yyy.DialogFragmentwWithListFragment " />
</LinearLayout>
2) 在 DialogFragmentwWithListFragment 中膨胀 dialog_fragment_with_list_fragment.xml
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
return inflater.inflate(R.layout.dialog_fragment_with_list_fragment, null);
}
3) 调用 DialogFragmentwWithListFragment 作为常规 DialogFragment:
3) invoke DialogFragmentwWithListFragment as regular DialogFragment:
DialogFragmentwWithListFragment dialogFragment = DialogFragmentwWithListFragment .newInstance();
dialogFragment.setRetainInstance(true);
dialogFragment.show(getFragmentManager(), "tag");
希望,它会有所帮助.
Hope, it helps.
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