我在这里挣扎和失败了十多分钟,我屈服了.我需要在 Swift 中将 Int 转换为 Character,但无法解决.
I've struggled and failed for over ten minutes here and I give in. I need to convert an Int to a Character in Swift and cannot solve it.
问题
你如何将一个 Int
(integer) 转换 (cast) 为一个 Character
(char) 在 Swift 中?
How do you convert (cast) an Int
(integer) to a Character
(char) in Swift?
说明性问题/任务挑战
生成一个 for 循环,打印字母 'A' 到 'Z',例如像这样:
Generate a for loop which prints the letters 'A' through 'Z', e.g. something like this:
for(var i:Int=0;i<26;i++) { //Important to note - I know
print(Character('A' + i)); //this is horrendous syntax...
} //just trying to illustrate! :)
不能将整数直接转换为 Character
实例,但可以从整数转换为 UnicodeScalar
到 Character
并再次返回:
You can't convert an integer directly to a Character
instance, but you can go from integer to UnicodeScalar
to Character
and back again:
let startingValue = Int(("A" as UnicodeScalar).value) // 65
for i in 0 ..< 26 {
print(Character(UnicodeScalar(i + startingValue)))
}
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