Sonar 告诉我用方法引用替换这个 lambda"
Sonar tells me "Replace this lambda with a method reference"
public class MyClass {
private List<SomeValue> createSomeValues(List<Anything> anyList) {
return anyList //
.stream() //
.map(anything -> createSomeValue(anything)) //
.collect(Collectors.toList());
}
private SomeValue createSomeValue(Anything anything) {
StatusId statusId = statusId.fromId(anything.getStatus().getStatusId());
return new SomeValue(anything.getExternId(), statusId);
}
}
这可能吗?我尝试了几件事,比如
Is this possible here? I tried several things, like
.map(MyClass::createSomeValue) //
但是我需要将方法更改为静态.而且我不是静态方法的忠实粉丝.
but I need to change the method to static then. And I am not a big fan of static methods.
SonarQube 的解释是:
Explanation of SonarQube is:
方法/构造函数引用比使用 lambda 更紧凑和可读,因此是首选.
Method/constructor references are more compact and readable than using lambdas, and are therefore preferred.
是的,你可以使用 this::createSomeValue
:
private List<SomeValue> createSomeValues(List<Anything> anyList) {
return anyList //
.stream() //
.map(this::createSomeValue) //
.collect(Collectors.toList());
}
这种方法参考称为"对特定对象的实例方法的引用".在这种情况下,您指的是实例 this
的方法 createSomeValue
.
This kind of method reference is called "Reference to an instance method of a particular object". In this case, you are referring to the method createSomeValue
of the instance this
.
使用 lambda 表达式是否更好"是一个见仁见智的问题.但是,您可以参考 this answer/brian-goetz">Brian Goetz 解释了为什么首先在语言中添加方法引用.
Whether it is "better" or not that using a lambda expression is a matter of opinion. However, you can refer to this answer written by Brian Goetz that explains why method-references were added in the language in the first place.
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