在 C++ 中，我可以声明一个内联"方法，编译器很可能会内联它.据我了解，Java 中没有这样的关键字.
In C++ I can declare a method "inline" and the compiler is likely to inline it. As far as I understand there is no such keyword in Java.
如果 JVM 决定这样做，内联是否完成?我能以某种方式影响这个决定吗?
Inlining is done if the JVM decides to do so? Can I influence this decision somehow?
其他几个答案表明只有 final 方法可以内联 - 这不是真的，因为 HotSpot 足够聪明，可以内联非final 方法，只要它们还没有被覆盖.当加载一个覆盖该方法的类时，它可以撤消其优化.显然，使方法最终意味着永远不需要......
A couple of the other answers have suggested that only final methods can be inlined - this is not true, as HotSpot is smart enough to be able to inline non-final methods so long as they haven't been overridden yet. When a class is loaded which overrides the method, it can undo its optimisation. Obviously making the method final mean that's never required...
基本上让 JVM 完成它的工作 - 它在确定内联位置方面可能比你要好得多.
Basically let the JVM do its job - it's likely to be a lot better at working out where to inline than you are.
您是否有过确信 JVM 做得不好的情况?假设您使用的是 HotSpot，您是否尝试过使用服务器版本而不是客户端?这可以产生巨大的差异.
Do you have a situation where you're convinced that the JVM isn't doing a good job? Assuming you're using HotSpot, have you tried using the server version instead of client? That can make a huge difference.
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