1. <legend id='lXe4t'><style id='lXe4t'><dir id='lXe4t'><q id='lXe4t'></q></dir></style></legend>
  2. <i id='lXe4t'><tr id='lXe4t'><dt id='lXe4t'><q id='lXe4t'><span id='lXe4t'><b id='lXe4t'><form id='lXe4t'><ins id='lXe4t'></ins><ul id='lXe4t'></ul><sub id='lXe4t'></sub></form><legend id='lXe4t'></legend><bdo id='lXe4t'><pre id='lXe4t'><center id='lXe4t'></center></pre></bdo></b><th id='lXe4t'></th></span></q></dt></tr></i><div id='lXe4t'><tfoot id='lXe4t'></tfoot><dl id='lXe4t'><fieldset id='lXe4t'></fieldset></dl></div>
      <bdo id='lXe4t'></bdo><ul id='lXe4t'></ul>

  3. <tfoot id='lXe4t'></tfoot>

    1. <small id='lXe4t'></small><noframes id='lXe4t'>

    2. Eclipse Plugin:如何获取当前选中项目的路径

      时间:2023-08-21

        <tfoot id='GANrR'></tfoot>

        <small id='GANrR'></small><noframes id='GANrR'>

        • <bdo id='GANrR'></bdo><ul id='GANrR'></ul>
            <tbody id='GANrR'></tbody>

        • <i id='GANrR'><tr id='GANrR'><dt id='GANrR'><q id='GANrR'><span id='GANrR'><b id='GANrR'><form id='GANrR'><ins id='GANrR'></ins><ul id='GANrR'></ul><sub id='GANrR'></sub></form><legend id='GANrR'></legend><bdo id='GANrR'><pre id='GANrR'><center id='GANrR'></center></pre></bdo></b><th id='GANrR'></th></span></q></dt></tr></i><div id='GANrR'><tfoot id='GANrR'></tfoot><dl id='GANrR'><fieldset id='GANrR'></fieldset></dl></div>
                <legend id='GANrR'><style id='GANrR'><dir id='GANrR'><q id='GANrR'></q></dir></style></legend>
              • 本文介绍了Eclipse Plugin:如何获取当前选中项目的路径的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!

                问题描述

                我正在编写一个 Eclipse 插件,它将在 Java 项目的上下文菜单中显示一个菜单项.我将plugin.xml写成如下:

                I am writing an Eclipse plugin that will display a menu item in the context menu for a Java Project. I have written the plugin.xml as follows:

                <plugin>
                   <extension
                         point="org.eclipse.ui.menus">
                      <menuContribution
                            locationURI="popup:org.eclipse.jdt.ui.PackageExplorer">
                         <dynamic
                               class="uk.co.dajohnston.plugin.classpathswitcher.menu.MenuContribution"
                               id="uk.co.dajohnston.plugin.classpathSwitcher.switchMenuContribution">
                            <visibleWhen>
                               <with
                                     variable="activeMenuSelection">
                                  <iterate>
                                     <adapt
                                           type="org.eclipse.jdt.core.IJavaProject">
                                     </adapt>
                                  </iterate>
                                  <count
                                        value="1">
                                  </count>
                               </with>
                            </visibleWhen>
                         </dynamic>
                      </menuContribution>
                   </extension>
                
                </plugin>
                

                所以我现在正在尝试编写扩展 CompoundContributionItemMenuContribution 类,以便我可以创建动态菜单,并且该菜单的内容将基于Java 项目的根目录中存在的一组文件.但我一直试图从 getContributionItems 方法中获取根目录的路径.

                So I am now trying to write the MenuContribution class which extends CompoundContributionItem so that I can create a dynamic menu and the contents of this menu are going to be based on a set of files that exist in the Java Project's root directory. But I am stuck trying to get the path to the root directory from within the getContributionItems method.

                基于 plugin.xml 文件,我可以保证只有在选择了单个 Java 项目时才会调用该方法,所以我需要做的就是获取当前选择,然后获取其绝对路径.有任何想法吗?或者有更好的方法吗?

                Based on the plugin.xml file I can be guarenteed that the method will only be called if a single Java Project is selected, so all I need to do is get the current selection and then get its absolute path. Any ideas? Or is there a better way to do this?

                推荐答案

                这应该让你更接近(如果不能为你完全解决它;))

                This should get you closer (if not solve it completely for you ;))

                    IWorkbenchWindow window = PlatformUI.getWorkbench().getActiveWorkbenchWindow();
                    if (window != null)
                    {
                        IStructuredSelection selection = (IStructuredSelection) window.getSelectionService().getSelection();
                        Object firstElement = selection.getFirstElement();
                        if (firstElement instanceof IAdaptable)
                        {
                            IProject project = (IProject)((IAdaptable)firstElement).getAdapter(IProject.class);
                            IPath path = project.getFullPath();
                            System.out.println(path);
                        }
                    }
                

                这篇关于Eclipse Plugin:如何获取当前选中项目的路径的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!

                上一篇:项目没有 project.properties 文件 下一篇:Subclipse 错误——Subversion 本机库不可用

                相关文章

              • <i id='vzX9x'><tr id='vzX9x'><dt id='vzX9x'><q id='vzX9x'><span id='vzX9x'><b id='vzX9x'><form id='vzX9x'><ins id='vzX9x'></ins><ul id='vzX9x'></ul><sub id='vzX9x'></sub></form><legend id='vzX9x'></legend><bdo id='vzX9x'><pre id='vzX9x'><center id='vzX9x'></center></pre></bdo></b><th id='vzX9x'></th></span></q></dt></tr></i><div id='vzX9x'><tfoot id='vzX9x'></tfoot><dl id='vzX9x'><fieldset id='vzX9x'></fieldset></dl></div>

                <small id='vzX9x'></small><noframes id='vzX9x'>

                1. <legend id='vzX9x'><style id='vzX9x'><dir id='vzX9x'><q id='vzX9x'></q></dir></style></legend>

                    <tfoot id='vzX9x'></tfoot>
                    • <bdo id='vzX9x'></bdo><ul id='vzX9x'></ul>