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        Integer.parseInt(String str) java.lang.NumberFormatException

        时间:2023-05-28

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                  本文介绍了Integer.parseInt(String str) java.lang.NumberFormatException: 错误的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!

                  问题描述

                  I keep getting number format expectations, even though I'm trimming the strings and they don't contain non numerical characters bizarrely it works for some numbers and not others. Below is an example of a string I get number format exception for. Also, any string starting with 0 e.g "0208405223", is returned 208405223, there's no zero anymore is that supposed to happen?

                  String n="3020857508";
                  Integer a = Integer.parseInt(n.trim());
                  System.out.println(a);
                  

                  This is the exception:

                  Exception in thread "main" java.lang.NumberFormatException: For input string: "3020857508"
                      at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
                      at java.lang.Integer.parseInt(Integer.java:583)
                      at java.lang.Integer.parseInt(Integer.java:615)
                      at JavaBeans.Main.main(Main.java:15)
                  

                  解决方案

                  It's because 3020857508 exceeds Integer.MAX_VALUE. You should use long to convert the string to number.

                  java> String n="3020857508";
                  //=> java.lang.String n = "3020857508"
                  java> Integer a = Integer.parseInt(n.trim());
                  //=> java.lang.NumberFormatException: For input string: "3020857508"
                  java> Integer.MAX_VALUE
                  //=> java.lang.Integer res2 = 2147483647
                  java> Long a = Long.parseLong(n.trim());
                  //=>java.lang.Long a = 3020857508
                  

                  The above is javarepl output.

                  If you are using JDK9 or above, you can see the same result in jshell.

                  jshell> String n="3020857508"
                  n ==> "3020857508"
                  
                  jshell> Integer a = Integer.parseInt(n.trim())
                  |  Exception java.lang.NumberFormatException: For input string: "3020857508"
                  |        at NumberFormatException.forInputString (NumberFormatException.java:65)
                  |        at Integer.parseInt (Integer.java:652)
                  |        at Integer.parseInt (Integer.java:770)
                  |        at (#2:1)
                  
                  jshell> Integer.MAX_VALUE
                  $3 ==> 2147483647
                  
                  jshell> Long a = Long.parseLong(n.trim());
                  a ==> 3020857508
                  

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