有没有办法获取原始响应 http 标头?
getHeaderField()
方法对我不起作用,因为服务器吐出多个Set-Cookie",其中一些会丢失.
getHeaderField()
方法对我不起作用
您是在 <代码>java.net.URLConnection,是吗?不,使用 URLconnection
无法获取原始 HTTP 响应标头.您需要退回到低级别的 Socket 编程.这是一个SSCCE,只需复制'n'paste'n'运行它.
包com.stackoverflow.q2307291;导入 java.io.BufferedReader;导入 java.io.IOException;导入 java.io.InputStreamReader;导入 java.io.OutputStreamWriter;导入 java.io.PrintWriter;导入 java.net.Socket;公共类测试{公共静态 void main(String[] args) 抛出 IOException {字符串主机名 = stackoverflow.com";国际端口 = 80;套接字套接字 = null;PrintWriter 作家 = null;BufferedReader 阅读器 = null;尝试 {套接字 = 新套接字(主机名,端口);writer = new PrintWriter(new OutputStreamWriter(socket.getOutputStream()));writer.println("GET/HTTP/1.1");writer.println("主机:" + 主机名);writer.println("接受:*/*");writer.println("用户代理:Java");//说实话.writer.println("");//重要,否则服务器会期望请求中包含更多内容.writer.flush();reader = new BufferedReader(new InputStreamReader(socket.getInputStream()));for (String line; (line = reader.readLine()) != null;) {if (line.isEmpty()) 中断;//当标题完成时停止.我们对所有的 HTML 不感兴趣.System.out.println(line);}} 最后 {if (reader != null) try { reader.close();} 捕捉(IOException logOrIgnore){}if (writer != null) { writer.close();}if (socket != null) try { socket.close();} 捕捉(IOException logOrIgnore){}}}}
为避免每个尝试此代码段的人都使 SO 过载,输出如下所示:
<上一页>HTTP/1.1 200 正常缓存控制:私有内容类型:文本/html;字符集=utf-8过期:2010 年 2 月 21 日星期日 20:39:08 GMT服务器:Microsoft-IIS/7.5日期:2010 年 2 月 21 日星期日 20:39:07 GMT连接:关闭内容长度:208969要了解有关以低级方式发送 HTTP 请求的更多信息,请阅读 HTTP 规范.
但是,您可能想使用 getHeaderFields()
方法来检索具有多个值的标头.<代码>getHeaderField() 即只返回最后一个值,根据链接的 API 文档.
列表<字符串>cookies = connection.getHeaderFields().get("Set-Cookie");
Is there any way to get raw response http header?
The getHeaderField()
method doesn't work for me, because server spits multiple 'Set-Cookie' and some of them get lost.
The
getHeaderField()
method doesn't work for me
You're asking this in the context of java.net.URLConnection
, is it? No, obtaining the raw HTTP response headers is not possible with URLconnection
. You'll need to fall back to low-level Socket programming. Here's an SSCCE, just copy'n'paste'n'run it.
package com.stackoverflow.q2307291;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.io.PrintWriter;
import java.net.Socket;
public class Test {
public static void main(String[] args) throws IOException {
String hostname = "stackoverflow.com";
int port = 80;
Socket socket = null;
PrintWriter writer = null;
BufferedReader reader = null;
try {
socket = new Socket(hostname, port);
writer = new PrintWriter(new OutputStreamWriter(socket.getOutputStream()));
writer.println("GET / HTTP/1.1");
writer.println("Host: " + hostname);
writer.println("Accept: */*");
writer.println("User-Agent: Java"); // Be honest.
writer.println(""); // Important, else the server will expect that there's more into the request.
writer.flush();
reader = new BufferedReader(new InputStreamReader(socket.getInputStream()));
for (String line; (line = reader.readLine()) != null;) {
if (line.isEmpty()) break; // Stop when headers are completed. We're not interested in all the HTML.
System.out.println(line);
}
} finally {
if (reader != null) try { reader.close(); } catch (IOException logOrIgnore) {}
if (writer != null) { writer.close(); }
if (socket != null) try { socket.close(); } catch (IOException logOrIgnore) {}
}
}
}
To avoid SO being overloaded by everyone trying this snippet, here's how the output will look like:
HTTP/1.1 200 OK Cache-Control: private Content-Type: text/html; charset=utf-8 Expires: Sun, 21 Feb 2010 20:39:08 GMT Server: Microsoft-IIS/7.5 Date: Sun, 21 Feb 2010 20:39:07 GMT Connection: close Content-Length: 208969
To learn more about sending HTTP requests the low-level way, read the HTTP specification.
However, you probably want to make use of getHeaderFields()
method instead to retrieve a header with multiple values. The getHeaderField()
namely only returns the last value, as per the linked API doc.
List<String> cookies = connection.getHeaderFields().get("Set-Cookie");
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