我有两个整数 x
和 y
.我需要计算 x/y
作为结果,我想获得浮动.例如,作为 3/2
的结果,我想要 1.5.我认为最简单(或唯一)的方法是将 x
和 y
转换为浮点类型.不幸的是,我找不到一个简单的方法来做到这一点.你能帮我解决这个问题吗?
I have two integers x
and y
. I need to calculate x/y
and as outcome I would like to get float. For example as an outcome of 3/2
I would like to have 1.5. I thought that easiest (or the only) way to do it is to convert x
and y
into float type. Unfortunately, I cannot find an easy way to do it. Could you please help me with that?
您只需要将至少一个操作数强制转换为浮点数:
You just need to cast at least one of the operands to a float:
float z = (float) x / y;
或
float z = x / (float) y;
或(不必要的)
float z = (float) x / (float) y;
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