Oracle 日期减法

问题描述

我将如何编写一个表达式，让我以天、小时、分钟、秒等为单位给出两个日期之间的差异?默认情况下，在 oracle 中减去两个日期以十进制形式返回天数.

How would i write an expression that gives me the difference between two dates in days, hours, minutes, seconds, etc? By default subtracting two dates in oracle returns days as a decmial.

推荐答案

那个小数点是提供的两个日期之间相差的天数.您可以做一些数学运算，将其转换为天、小时、分钟、秒等.

That decimal is the number of days difference between the two dates provided. You can do a little math to convert that to days, hours, minutes, seconds, etc.

编辑:我知道你在找什么.我确定有更简单的方法，但我可能会这样完成:

EDIT: I see what you're looking for. I'm sure there's an easier way, but I would probably accomplish it thusly:

select trunc(5.3574585) days, 
       trunc(mod((5.3574585) * 24, 24)) hours, 
       trunc(mod((5.3574585) * 24 * 60, 60)) minutes, 
       trunc(mod((5.3574585) * 24 * 60 * 60, 60)) seconds 
  from dual;

...其中 5.3574585 是减法返回的天数...

...where 5.3574585 is the number of days returned by the subtraction...

注意:这并没有经过真正的测试，这是我的想法.

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