需要有一个存储过程来调用 SQL Server 代理作业并返回该作业是否成功运行.
Need to have a stored procedure that calls a SQL Server Agent Job and returns whether or not the job ran successfully or not.
到目前为止我有
So far I have
CREATE PROCEDURE MonthlyData
AS
EXEC msdb.dbo.sp_start_job N'MonthlyData'
WAITFOR DELAY '000:04:00'
EXEC msdb.dbo.sp_help_jobhistory @job_name = 'MonthlyData'
GO
哪个开始工作,如果工作成功与否,返回的最佳方法是什么?
Which starts the job, whats the best way to get back if the job ran successfully or not?
Ok 进行了编辑并使用了 WAITFOR DELAY,因为该作业通常在 3-4 分钟之间运行,从不超过 4 分钟.该作业是否有更有效的方法来完成?
Ok made an edit and used WAITFOR DELAY as the job normally runs between 3-4 mins never longer than 4. Does the job but is there a more efficient way to do it?
您可以运行查询:
EXEC msdb.dbo.sp_help_jobhistory
@job_name = N'MonthlyData'
它将返回一列 run_status.状态为:
It'll return a column run_status. Statuses are:
0 - Failed
1 - Succeeded
2 - Retry
3 - Canceled
有关 MSDN
编辑:您可能想要轮询您的工作并确保它已执行.您可以从 sp_help_job 过程中获取此信息.当此过程返回4
状态时,表示作业空闲.然后检查它的运行状态是安全的.
EDIT: You might want to to poll your job and make sure it's executed. You can get this information from sp_help_job procedure. When this procedure returns status of 4
it means the job is idle.
Then it's safe to check for it's run status.
您可以使用以下代码进行投票:
You can poll using following code:
DECLARE @job_status INT
SELECT @job_status = current_execution_status FROM OPENROWSET('SQLNCLI', 'Server=.;Trusted_Connection=yes;','exec msdb.dbo.sp_help_job @job_name = ''NightlyBackups''')
WHILE @job_status <> 4
BEGIN
WAITFOR DELAY '00:00:03'
SELECT @job_status = current_execution_status FROM OPENROWSET('SQLNCLI', 'Server=.;Trusted_Connection=yes;','exec msdb.dbo.sp_help_job @job_name = ''NightlyBackups''')
END
EXEC msdb.dbo.sp_help_jobhistory
@job_name = N'NightlyBackups' ;
GO
此代码将检查状态,等待 3 秒钟,然后重试.一旦状态为 4,我们就知道工作已完成,可以安全地检查工作历史记录.
This code will check for the status, wait for 3 seconds and try again. Once we get status of 4 we know the job is done and it's safe to check for the job history.
这篇关于从存储过程执行 SQL Server 代理作业并返回作业结果的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!