全部我想显示特定 id 的最后 5 个输入数据.我的 sql 查询是,
all I want to display last 5 entered data for specific id. My sql query is,
SELECT id, name, form_id, DATE(updated_at) as date
FROM wp_frm_items
WHERE user_id = 11 && form_id=9
ORDER BY updated_at DESC
updated_at
是 DATETIME
updated_at
is DATETIME
它显示按日期而不是按时间排序的最后 5 个条目.在同一天,然后按字母顺序排序.
It displays last 5 entry sort by date not by time. On same date then it is sorting alphabetically.
假设我在同一日期有 3 个条目,但时间不同
Suppose i have 3 entries in same date with diff time
说吧
Ajay 1/3/2012 1:15
John 1/3/2012 1:00
Bony 1/3/2012 1:10
查询上面的查询后
我得到的是
Ajay 1/3/2012 1:15
Bony 1/3/2012 1:10
John 1/3/2012 1:00
按日期然后按字母顺序排序
Sort by date then after alphabetically
我想要的是这个..
John 1/3/2012 1:00
Bony 1/3/2012 1:10
Ajay 1/3/2012 1:15
也按日期和时间排序...
Sorted by date and time also...
如果你想要最后5行,升序排列,你需要一个子查询:
If you want the last 5 rows, ordered in ascending order, you need a subquery:
SELECT *
FROM
( SELECT id, name, form_id, DATE(updated_at) AS updated_date, updated_at
FROM wp_frm_items
WHERE user_id = 11
AND form_id=9
ORDER BY updated_at DESC
LIMIT 5
) AS tmp
ORDER BY updated_at
<小时>
在第 10 次阅读问题后,这可能(只是可能)是您想要的.按日期降序排序,然后按时间(同一日期)升序排序:
After reading the question for 10th time, this may be (just maybe) what you want. Order by Date descending and then order by time (on same date) ascending:
SELECT id, name, form_id, DATE(updated_at) AS updated_date
FROM wp_frm_items
WHERE user_id = 11
AND form_id=9
ORDER BY DATE(updated_at) DESC
, updated_at ASC
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