我创建了用户表
CREATE TABLE `user` (
`id` BIGINT UNSIGNED NOT NULL AUTO_INCREMENT ,
`first_name` VARBINARY(100) NULL ,
`address` VARBINARY(200) NOT NULL ,
PRIMARY KEY (`id`))
ENGINE = InnoDB
DEFAULT CHARACTER SET = utf8
COLLATE = utf8_general_ci;
我插入了一行:
INSERT into user (first_name, address) VALUES (AES_ENCRYPT('Obama', 'usa2010'),AES_ENCRYPT('Obama', 'usa2010'));
要选择我使用的这一行:
To select this row i used:
SELECT AES_DECRYPT(first_name, 'usa2010'), AES_DECRYPT(address, 'usa2010') from user;
我得到以下结果.我需要做什么才能看到我的数据.我看不到任何数据.
I am getting the following result.What i need to do see my data.No data is visible for me.
根据手册:
AES_ENCRYPT() 加密一个字符串并返回一个二进制字符串.AES_DECRYPT() 解密加密后的字符串并返回原始字符串.
AES_ENCRYPT() encrypts a string and returns a binary string. AES_DECRYPT() decrypts the encrypted string and returns the original string.
我不知道为什么在你的情况下它仍然返回一个二进制字符串.不管怎样,试试这个:
I don't know why it is still returning a binary string in your case. Anyway, try this:
SELECT *,
CAST(AES_DECRYPT(first_name, 'usa2010') AS CHAR(50)) first_name_decrypt
FROM user
并使用first_name_decrypt
而不是first_name
.
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