有没有一种方法可以在 MySQL 中进行查询,以秒为单位提供两个时间戳之间的差异,或者我需要在 PHP 中执行此操作吗?如果是这样,我将如何去做?
Is there a way I can make a query in MySQL that will give me the difference between two timestamps in seconds, or would I need to do that in PHP? And if so, how would I go about doing that?
您可以使用 TIMEDIFF()
和 TIME_TO_SEC()
函数如下:
You could use the TIMEDIFF()
and the TIME_TO_SEC()
functions as follows:
SELECT TIME_TO_SEC(TIMEDIFF('2010-08-20 12:01:00', '2010-08-20 12:00:00')) diff;
+------+
| diff |
+------+
| 60 |
+------+
1 row in set (0.00 sec)
您也可以使用 UNIX_TIMESTAMP()
函数为 @Amber 在另一个答案中建议:
SELECT UNIX_TIMESTAMP('2010-08-20 12:01:00') -
UNIX_TIMESTAMP('2010-08-20 12:00:00') diff;
+------+
| diff |
+------+
| 60 |
+------+
1 row in set (0.00 sec)
如果您使用 TIMESTAMP
数据类型,我猜 UNIX_TIMESTAMP()
解决方案会稍微快一点,因为 TIMESTAMP
值是已经存储为一个整数,表示自纪元以来的秒数(来源).引用 docs:
If you are using the TIMESTAMP
data type, I guess that the UNIX_TIMESTAMP()
solution would be slightly faster, since TIMESTAMP
values are already stored as an integer representing the number of seconds since the epoch (Source). Quoting the docs:
当 UNIX_TIMESTAMP()
用于 TIMESTAMP
列时,函数直接返回内部时间戳值,没有隐式的字符串到 Unix 时间戳"转换.
When
UNIX_TIMESTAMP()
is used on aTIMESTAMP
column, the function returns the internal timestamp value directly, with no implicit "string-to-Unix-timestamp" conversion.
请记住 TIMEDIFF()
返回TIME
的数据类型.TIME
值的范围可以从 '-838:59:59' 到 '838:59:59'(大约 34.96 天)
Keep in mind that TIMEDIFF()
return data type of TIME
. TIME
values may range from '-838:59:59' to '838:59:59' (roughly 34.96 days)
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