我有 player
-s 与 skill
-s 多对多关系的表格
I have table with player
-s in many-to-many relation with skill
-s
目标是通过一个查询列出玩家及其前三项技能".
The goal is to list the players and their "top 3 skills" with a single query.
小提琴
create table player(
id int primary key
);
create table skill(
id int primary key,
title varchar(100)
);
create table player_skills (
id int primary key,
player_id int,
skill_id int,
value int
);
查询:
SELECT
p.id,
group_concat(s.title SEPARATOR ', ') as skills
FROM player p
LEFT JOIN player_skills ps ON ps.player_id = p.id
LEFT JOIN skill s ON s.id = ps.skill_id
WHERE ps.value > 2
-- skills limit 3 some how ...
group by p.id
order by s.id
-- expected result
-- player_ID, skills
-- 1 , 'one'
-- 2 , 'one'
-- 3 , 'two, three, four'
正如您在小提琴中所见,查询结果仅缺少 3 个技能的限制.
我尝试了几种子查询的变体.. 加入等等,但没有效果.
As you can see in the fiddle the result of the query is missing only the limit of 3 skills.
I tried several variation of sub queries.. joins and so but with no effect.
一种有点老套的方法是对 GROUP_CONCAT
的结果进行后处理:
One somewhat hacky way to do it is to post-process the result of GROUP_CONCAT
:
substring_index(group_concat(s.title SEPARATOR ','), ',', 3) as skills
当然,这假设您的技能名称不包含逗号并且它们的数量相当小.
Of course this assumes that your skill names don't contain commas and that their amount is reasonably small.
小提琴
功能请求,GROUP_CONCAT
支持不幸的是,显式的 LIMIT
子句仍未解决.
A feature request for GROUP_CONCAT
to support an explicit LIMIT
clause is unfortunately still not resolved.
更新:正如用户 Strawberry 指出的那样,表 player_skills
应该将元组 (player_id, Skill_id)
作为其主键,否则模式允许将同一技能多次分配给玩家,在这种情况下 group_concat
不会按预期工作.
UPDATE: As user Strawberry points out, the table player_skills
should have the tuple (player_id, skill_id)
as its primary key, otherwise the schema allows for the same skill to be assigned to a player multiple times, in which case group_concat
would not work as expected.
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