一个表包含一个 Title
字段和一个 Tags
字段.标签是通过潜在狄利克雷分配(LDA)从文档中生成的,可以是例如鱼、烤箱、时间"、烧烤、啤酒"或肉、烧烤".标签的长度不固定.
A table contains a Title
field and a Tags
field. The tags are generated via latent Dirichlet allocation (LDA) from documents and can be e.g. 'fish, oven, time', 'BBQ, beer' or ' meat, BBQ'. The length of the tags is not fixed.
给定一组标签,无论标签的顺序如何,如何找到匹配的标签数量最多的记录?
Given a set of tags, how to find the record with the maximum amount of tags matching no matter the order of the tags?
因此,如果给出BBQ, meat",最好的结果应该是meat, BBQ".如果给出'BBQ,fish, cream',则可以返回所有三个记录(它们都有一个匹配的标签).
So, if 'BBQ, meat' is given the best result should be 'meat, BBQ'. If 'BBQ, fish, cream' is given all three records can be returned (they all have one matching tag).
使用这个函数并创建这个>
Use this function and Create this one
CREATE FUNCTION dbo.getCountOfMatch ( @mainString VARCHAR(MAX), @searchString nvarchar(max))
RETURNS
INT
AS
BEGIN
DECLARE @returnCount INT
SELECT
@returnCount = COUNT(1)
FROM
splitstring(@mainString) A INNER JOIN
splitstring(@searchString) B ON A.Name = B.Name
RETURN @returnCount
END
和
SELECT TOP 1 // What you want
Title,
Tags
FROM
(
SELECT
A.Title,
A.Tags,
dbo.getCountOfMatch(A.Tags, @search) CountTags -- The number of matches.
FROM
TABLE A
) B
ORDER BY B.CountTags DESC
更新
DECLARE @searchText NVARCHAR(MAX) = 'BBQ, meat'
DECLARE @query NVARCHAR(MAX) = '
SELECT
*
FROM
Table
WHERE '
SELECT
@query +=
(
SELECT
'Tags like ''%' + A.Name + '%'' AND ' -- Dont forget trim!
FROM
splitstring(@searchText) A
FOR XML PATH ('')
)
SELECT @query = LEFT(@query, LEN(@query) - 4) + 'ORDER BY LEN(Tags)' -- For exactly matching: LEN(Tags) = LEN(@searchText)
EXEC sp_executesql @query
查询的样子;
SELECT
*
FROM
Table
WHERE
Tags like '%BBQ%' AND
Tags like '%meat%'
ORDER BY LEN(Tags)
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