您好,我有以下 Xml 需要反序列化:
Hi I have the following Xml to deserialize:
<RootNode>
<Item
Name="Bill"
Age="34"
Job="Lorry Driver"
Married="Yes" />
<Item
FavouriteColour="Blue"
Age="12"
<Item
Job="Librarian"
/>
</RootNote>
当我不知道键名或会有多少属性时,如何使用属性键值对列表反序列化 Item 元素?
How can I deserialize the Item element with a list of attribute key value pairs when I dont know the key names or how many attributes there will be?
您可以使用 XmlAnyAttribute
属性指定任意属性将被序列化和反序列化为 XmlAttribute []
属性或使用 XmlSerializer
时的字段.
You can use the XmlAnyAttribute
attribute to specify that arbitrary attributes will be serialized and deserialized into an XmlAttribute []
property or field when using XmlSerializer
.
例如,如果要将属性表示为 Dictionary
,则可以定义 Item
和 RootNode
类如下,使用代理 XmlAttribute[]
属性将字典与所需的 XmlAttribute
数组相互转换:
For instance, if you want to represent your attributes as a Dictionary<string, string>
, you could define your Item
and RootNode
classes as follows, using a proxy XmlAttribute[]
property to convert the dictionary from and to the required XmlAttribute
array:
public class Item
{
[XmlIgnore]
public Dictionary<string, string> Attributes { get; set; }
[XmlAnyAttribute]
public XmlAttribute[] XmlAttributes
{
get
{
if (Attributes == null)
return null;
var doc = new XmlDocument();
return Attributes.Select(p => { var a = doc.CreateAttribute(p.Key); a.Value = p.Value; return a; }).ToArray();
}
set
{
if (value == null)
Attributes = null;
else
Attributes = value.ToDictionary(a => a.Name, a => a.Value);
}
}
}
public class RootNode
{
[XmlElement("Item")]
public List<Item> Items { get; set; }
}
原型小提琴.
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