使用 C#:
如果我有圆心坐标和半径,我如何获得任意给定度数的圆边缘的 (x, y) 坐标?
How do I get the (x, y) coordinates on the edge of a circle for any given degree, if I have the center coordinates and the radius?
可能涉及到 SIN、TAN、COSIN 和其他十年级数学... :)
There is probably SIN, TAN, COSIN and other grade ten math involved... :)
以下是适用于任何语言的数学解决方案:
Here's the mathematical solution which can be applied in any language:
x = x0 + r * cos(theta)
y = y0 + r * sin(theta)
x0
和 y0
是圆心坐标,r
是半径,theta
在弧度.角度是从 x 轴逆时针方向测量的.
x0
and y0
are the coordinates of the centre, r
is the radius, and theta
is in radians. The angle is measured anticlockwise from the x-axis.
这是 C# 的代码,特别是如果您的角度以度为单位:
This is the code for C# specifically if your angle is in degrees:
double x = x0 + r * Math.Cos(theta * Math.PI / 180);
double y = y0 + r * Math.Sin(theta * Math.PI / 180);
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