我有一组点.我想将它们分成 2 个不同的集合.为此,我选择了两个点(a 和 b)并在它们之间画一条假想线.现在我想把这条线左边的所有点放在一组中,把这条线右边的点放在另一组中.
I have a set of points. I want to separate them into 2 distinct sets. To do this, I choose two points (a and b) and draw an imaginary line between them. Now I want to have all points that are left from this line in one set and those that are right from this line in the other set.
我如何判断任何给定点 z 是在左边还是在右边?我试图计算 a-z-b – 之间的角度.小于 180 的角度在右侧,大于 180 的角度在左侧.但由于 ArcCos 的定义,计算出的角度总是小于 180°.是否有计算大于 180° 的角度的公式(或任何其他选择右侧或左侧的公式)?
How can I tell for any given point z whether it is in the left or in the right set? I tried to calculate the angle between a-z-b – angles smaller than 180 are on the right hand side, greater than 180 on the left hand side – but because of the definition of ArcCos, the calculated angles are always smaller than 180°. Is there a formula to calculate angles greater than 180° (or any other formula to chose right or left side)?
使用向量行列式的符号(AB,AM)
,其中M(X,Y)
为查询点:
Use the sign of the determinant of vectors (AB,AM)
, where M(X,Y)
is the query point:
position = sign((Bx - Ax) * (Y - Ay) - (By - Ay) * (X - Ax))
一行是0
,一侧是+1
,另一侧是-1
.
It is 0
on the line, and +1
on one side, -1
on the other side.
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