我想向 RabbitMQ 服务器发送一条消息,然后等待回复消息(在回复"队列上).当然,我不想永远等待,以防处理这些消息的应用程序出现故障 - 需要超时.这听起来像是一项非常基本的任务,但我找不到这样做的方法.我现在遇到了 py-amqplib 和 RabbitMQ .NET 客户端.
I'd like to send a message to a RabbitMQ server and then wait for a reply message (on a "reply-to" queue). Of course, I don't want to wait forever in case the application processing these messages is down - there needs to be a timeout. It sounds like a very basic task, yet I can't find a way to do this. I've now run into this problem with both py-amqplib and the RabbitMQ .NET client.
到目前为止,我得到的最佳解决方案是使用 basic_get
和中间的 sleep
进行轮询,但这很丑:
The best solution I've got so far is to poll using basic_get
with sleep
in-between, but this is pretty ugly:
def _wait_for_message_with_timeout(channel, queue_name, timeout):
slept = 0
sleep_interval = 0.1
while slept < timeout:
reply = channel.basic_get(queue_name)
if reply is not None:
return reply
time.sleep(sleep_interval)
slept += sleep_interval
raise Exception('Timeout (%g seconds) expired while waiting for an MQ response.' % timeout)
肯定有更好的方法吗?
我刚刚在 carrot
中添加了对 amqplib
的超时支持.
I just added timeout support for amqplib
in carrot
.
这是 amqplib.client0_8.Connection
的子类:
http://github.com/询问/carrot/blob/master/carrot/backends/pyamqplib.py#L19-97
wait_multi
是 channel.wait
的一个版本,能够接收任意数字频道.
wait_multi
is a version of channel.wait
able to receive on an arbitrary number
of channels.
我想这可能会在某个时候在上游合并.
I guess this could be merged upstream at some point.
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