我正在使用 JSON.NET 和 C# 5.我需要将对象列表序列化/反序列化为行分隔的 json.http://en.wikipedia.org/wiki/Line_Delimited_JSON.例如,
I am using JSON.NET and C# 5. I need to serialize/de-serialize list of objects into line delimited json. http://en.wikipedia.org/wiki/Line_Delimited_JSON. Example,
{"some":"thing1"}
{"some":"thing2"}
{"some":"thing3"}
和
{"kind": "person", "fullName": "John Doe", "age": 22, "gender": "Male", "citiesLived": [{ "place": "Seattle", "numberOfYears": 5}, {"place": "Stockholm", "numberOfYears": 6}]}
{"kind": "person", "fullName": "Jane Austen", "age": 24, "gender": "Female", "citiesLived": [{"place": "Los Angeles", "numberOfYears": 2}, {"place": "Tokyo", "numberOfYears": 2}]}
为什么我需要它,因为它的 Google BigQuery 要求 https://cloud.google.com/bigquery/preparing-data-for-bigquery
Why I needed because its Google BigQuery requirement https://cloud.google.com/bigquery/preparing-data-for-bigquery
更新:我发现的一种方法是单独序列化每个对象并在最后加入换行符.
Update: One way I found is that serialize each object seperataly and join in the end with new-line.
您可以通过使用 JsonTextReader
手动解析 JSON 并将 SupportMultipleContent
标志设置为 真
.
You can do so by manually parsing your JSON using JsonTextReader
and setting the SupportMultipleContent
flag to true
.
如果我们查看您的第一个示例,并创建一个名为 Foo
的 POCO:
If we look at your first example, and create a POCO called Foo
:
public class Foo
{
[JsonProperty("some")]
public string Some { get; set; }
}
这就是我们解析它的方式:
This is how we parse it:
var json = "{"some":"thing1"}
{"some":"thing2"}
{"some":"thing3"}";
var jsonReader = new JsonTextReader(new StringReader(json))
{
SupportMultipleContent = true // This is important!
};
var jsonSerializer = new JsonSerializer();
while (jsonReader.Read())
{
Foo foo = jsonSerializer.Deserialize<Foo>(jsonReader);
}
如果您想要项目列表作为结果,只需将每个项目添加到 while
循环内的列表中即可.
If you want list of items as result simply add each item to a list inside the while
loop to your list.
listOfFoo.Add(jsonSerializer.Deserialize<Foo>(jsonReader));
注意:对于 Json.Net 10.0.4 及更高版本,相同的代码还支持逗号分隔的 JSON 条目,请参阅 如何反序列化狡猾的 JSON(带有不正确引用的字符串和缺少括号)?)
Note: with Json.Net 10.0.4 and later same code also supports comma separated JSON entries see How to deserialize dodgy JSON (with improperly quoted strings, and missing brackets)?)
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