我无法预测我的 MongoDB 文档将包含哪些字段.所以我不能再用 BsonID
类型的 _id
字段创建对象.我发现创建一个 Dictionary (HashTable) 并在其中添加我的 DateTime 和 String 对象非常方便,我需要多少次都可以.
I am in a situation where I can't predict which fields my MongoDB document is going to have. So I can no longer create an object with an _id
field of type BsonID
.
I find it very convenient to create a Dictionary (HashTable) and add my DateTime and String objects inside, as many times as I need it.
然后我尝试将生成的 Dictionary 对象插入 MongoDb,但默认序列化失败.
I then try to insert the resulting Dictionary object into MongoDb, but default serialization fails.
这是我的 HashTable 类型对象(类似于字典,但里面有不同的类型):
Here's my object of Type HashTable (like a Dictionary, but with varied types inside):
{ "_id":"",
"metadata1":"asaad",
"metadata2":[],
"metadata3":ISODate("somedatehere")}
我得到的驱动程序的错误是:
And the error from the driver I get is:
Serializer DictionarySerializer 期望 DictionarySerializationOptions 类型的序列化选项,而不是 DocumentSerializationOptions
Serializer DictionarySerializer expected serialization options of type DictionarySerializationOptions, not DocumentSerializationOptions
我用谷歌搜索了它,但找不到任何有用的东西.我做错了什么?
I googled it, but couldn't find anything useful. What am I doing wrong?
驱动需要能够找到_id字段.您可以创建一个只有两个属性的 C# 类:Id 和 Values.
The driver needs to be able to find the _id field. You could create a C# class that has just two properties: Id and Values.
public class HashTableDocument
{
public ObjectId Id { get; set; }
[BsonExtraElements]
public Dictionary<string, object> Values { get; set; }
}
请注意,我们必须使用 Dictionary<string, object>而不是哈希表.
Note that we have to use Dictionary<string, object> instead of Hashtable.
然后您可以使用如下代码插入文档:
You could then use code like the following to insert a document:
var document = new HashTableDocument
{
Id = ObjectId.GenerateNewId(),
Values = new Dictionary<string, object>
{
{ "metadata1", "asaad" },
{ "metadata2", new object[0] },
{ "metadata3", DateTime.UtcNow }
}
};
collection.Insert(document);
我们可以使用 MongoDB shell 来确认插入的文档是否具有所需的形式:
We can use the MongoDB shell to confirm that the inserted document has the desired form:
> db.test.find().pretty()
{
"_id" : ObjectId("518abdd4e447ad1f78f74fb1"),
"metadata1" : "asaad",
"metadata2" : [ ],
"metadata3" : ISODate("2013-05-08T21:04:20.895Z")
}
>
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