如何二进制序列化器自定义类

时间:2023-03-29
本文介绍了如何二进制序列化器自定义类的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!

问题描述

我有这个自定义类:

public class MyClass
{ 
    private byte byteValue;
    private int intValue;
    private MyClass myClass1= null;
    private MyClass myClass2 = null;
}

显然我也有构造函数和 get/set 方法.

obviously I also have constructor and get/set methods.

在我的主窗体中,我初始化了很多 MyClass 对象(请注意,在 MyClass 对象中我引用了其他 2 个 MyClass 对象).初始化后,我遍历第一个 MyClass 项,例如将其称为root".因此,例如,我会执行以下操作:

In my main form I initialize a lot of MyClass object (note that in MyClass object I have reference to other 2 MyClass objects). After initialization I iterate through a first MyClass item, call it for instance "root". So, for example I do something like:

MyClass myClassTest = root.getMyClass1();
MyClass myClassTest2 = myClassTest.getMyClass1();

等等.

不,我想存储在二进制文件中,所有的 MyClass 对象都被实例化,以便在软件重启后再次获取它们.

No I want to store in a binary file, all the MyClass object instantiated, in order to get them again after software restart.

我完全不知道如何做到这一点,有人可以帮助我吗?谢谢.

I have totally no idea on how to do this, can someone please help me? Thanks.

推荐答案

首先在类声明前添加[Serializable]属性.有关属性的更多信息,请访问:https://msdn.microsoft.com/en-我们/图书馆/z0w1kczw.aspx

First add the attribute [Serializable] before the class declaration. More about the attributes go to: https://msdn.microsoft.com/en-us/library/z0w1kczw.aspx

[Serializable]
public class MyClass
{ 
    private byte byteValue;
    private int intValue;
    private MyClass myClass1= null;
    private MyClass myClass2 = null;
}

注意:所有类成员也必须是可序列化的.要将对象序列化为二进制,您可以使用以下代码示例:

Note: all the class members must be also serializable. For serializing the object to binary you can use the following code sample:

using (Stream stream = File.Open(serializationPath, FileMode.Create))
        {
            var binaryFormatter = new System.Runtime.Serialization.Formatters.Binary.BinaryFormatter();
            binaryFormatter.Serialize(stream, objectToSerialize);
            stream.Close();
        }

对于从二进制反序列化:

And for the deserializing from binary:

using (Stream stream = File.Open(serializationFile, FileMode.Open))
        {
            var binaryFormatter = new System.Runtime.Serialization.Formatters.Binary.BinaryFormatter();

            deserializedObject = (MyClass)binaryFormatter.Deserialize(stream);
        }

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