将 XML 反序列化为 XSD 生成的类的问题

问题描述

我有一个相当详细的 xml 文件.下面是顶级节点(我已经包含了椭圆，因为较低级别的节点都格式正确并正确填充了数据):

I have a rather detailed xml file. Below is the top level nodes (I have included the ellipse as the lower level nodes are all well formed and properly filled with data):

<?xml version="1.0" encoding="UTF-8"?>
<config>
    <Models>...</Models>
    <Data>...</Data>
</config>

我已经使用 Visual Studio 2008 命令提示符创建了一个 xsd 文件:

I have created an xsd file from using the Visual Studio 2008 command prompt:

xsd sample.xml

这会生成 xsd 文件就好了.然后我使用以下命令从 xsd 自动生成类:

This generates the xsd file just fine. I then auto generate classes from the xsd with the command:

xsd sample.xsd /classes

为了将xml文件反序列化为类对象，我在helper类中使用了read函数:

For the deserialization of the xml file into a class object, I'm using the read function in the helper class:

public class XmlSerializerHelper<T>
{
    public Type _type;

    public XmlSerializerHelper()
    {
        _type = typeof(T);
    }

    public void Save(string path, object obj)
    {
        using (TextWriter textWriter = new StreamWriter(path))
        {
            XmlSerializer serializer = new XmlSerializer(_type);
            serializer.Serialize(textWriter, obj);
        }
    }

    public T Read(string path)
    {
        T result;
        using (TextReader textReader = new StreamReader(path))
        {
            XmlSerializer deserializer = new XmlSerializer(_type);
            result = (T)deserializer.Deserialize(textReader);
        }
        return result;
    }
}

尝试反序列化时:

var helper = new XmlSerializerHelper<configModels>();
var obj = new configModels();
obj = helper.Read(filepath);

我收到一个错误，我推断是因为反序列化器正在寻找模型"节点，但相应的类名是作为根节点和模型"节点 (configModels) 的组合生成的.为什么生成的类名是这样的?

I receive an error that I have deduced is because the deserializer is looking for the 'Models' node but the corresponding class name was generated as a combination of the root node and the 'Model' node (configModels). Why are the class names generated like this?

我尝试使用以下方法从顶部节点反序列化:

I tried to deserialize from the top node using:

var helper = new XmlSerializerHelper<config>();
var obj = new config();
obj = helper.Read(filepath);

不幸的是，这会导致一系列错误，如下所示:

Unfortunately, this the results in a slew of errors like the following:

System.InvalidOperationException was unhandled by user code
Message="Unable to generate a temporary class (result=1).
error CS0030: Cannot convert type 'Application.Lease[]' to 'Application.Lease'
error CS0030: Cannot convert type 'Application.CashFlow[]' to 'Application.CashFlow'
...ect.

有人可以指导我解决我的 xsd 自动生成可能做错的地方吗?

Can somebody steer me towards what I might be doing wrong with my xsd auto-generating?

推荐答案

XSD.EXE 是一个好的开始 - 但它远非完美.此外，根据您提供的 XML，XSD.EXE 无法始终确定某事物是对象的单个实例，还是对象的开放式数组.

XSD.EXE is a good start - but it's far from perfect. Also, based on the XML you provided, XSD.EXE can't always decide for sure whether something is a single instance of an object, or an open-ended array of objects.

这似乎是您的两个元素的情况 - Application.Lease 和 Application.CashFlow.它们在生成的 XSD 文件中是如何定义的?这对你有意义吗?很可能，您必须添加一些提示，例如:

This seems to be the case for your two elements - Application.Lease and Application.CashFlow. How are they defined in the generated XSD file? Does that make sense to you? Quite possibly, you'd have to add a little hints, such as:

<xs:element name="Lease" minOccurs="0" maxOccurs="1" />

对于可选属性，仅出现 0 次或 1 次.对于 xsd.exe 工具来说，仅基于单个 XML 示例文件，这样的事情真的很难弄清楚.

for an optional property, that's zero or one occurences only. Things like that are really hard for the xsd.exe tool to figure out based on just a single XML sample file.

马克

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